俄罗斯方块之四——方块子类

父类我们分析完了，现在来看看子类。父类里有两个抽象方法，以L型为例（其他类型同理，不仅7种类型）BlockL子类：

4.1首先以0所在的小方块为基础朝北，顺时针旋转。用数字标记的小方块相对位置不变。 （如图）











Code:

public override void Init(Direction dir)

{

Square s1 = new Square(), s2 = new Square(), s3 = new Square(), s4 = new Square();

if (dir == Direction.North)

{

/*

* 1

* 0

* 2 3

*/

s1.Location = this.Location;

Squares.Add(s1);

s2.Location = new Point(s1.Location.X, s1.Location.Y - Game.Side);

Squares.Add(s2);

s3.Location = new Point(s1.Location.X , s1.Location.Y+Game.Side);

Squares.Add(s3);

s4.Location = new Point(s1.Location.X + Game.Side, s1.Location.Y + Game.Side);

Squares.Add(s4);

}

else if (dir == Direction.East)

{

/*

* 2 0 1

* 3

*/

s1.Location = this.Location;

Squares.Add(s1);

s2.Location = new Point(s1.Location.X + Game.Side, s1.Location.Y);

Squares.Add(s2);

s3.Location = new Point(s1.Location.X - Game.Side, s1.Location.Y);

Squares.Add(s3);

s4.Location = new Point(s1.Location.X - Game.Side, s1.Location.Y + Game.Side);

Squares.Add(s4);

}

else if (dir == Direction.South)

{

/*

* 3 2

* 0

* 1

*/

s1.Location = this.Location;

Squares.Add(s1);

s2.Location = new Point(s1.Location.X, s1.Location.Y + Game.Side);

Squares.Add(s2);

s3.Location = new Point(s1.Location.X , s1.Location.Y - Game.Side);

Squares.Add(s3);

s4.Location = new Point(s1.Location.X - Game.Side, s1.Location.Y - Game.Side);

Squares.Add(s4);

}

else

{

/*

* 3

* 1 0 2

*/

s1.Location = this.Location;

Squares.Add(s1);

s2.Location = new Point(s1.Location.X - Game.Side, s1.Location.Y);

Squares.Add(s2);

s3.Location = new Point(s1.Location.X + Game.Side, s1.Location.Y );

Squares.Add(s3);

s4.Location = new Point(s1.Location.X + Game.Side, s1.Location.Y - Game.Side);

Squares.Add(s4);

}

}

4.2 旋转时首先记录旋转钱的位置和方向，然后判读能否旋转。不能旋转则回到原来的状态。旋转是以图示的0位置的小方块为中转动。参考代码如下：


顺时针旋转




Code:

public override void Ratate()

{

Direction oldDir = Direction;

Square s1 = Squares[0];

List<Square> oldSquares = new List<Square>();

foreach (Square s in Squares)

{

Square tempSquares = new Square();

tempSquares.Location = new Point(s.Location.X, s.Location.Y);

oldSquares.Add(tempSquares);

}

HideBlock();



if (Direction == Direction.North)

{

/*

* 1

* 0

* 2 3

*/

Direction = Direction.East;

Squares[1].Location = new Point(s1.Location.X + Game.Side, s1.Location.Y);

Squares[2].Location = new Point(s1.Location.X - Game.Side, s1.Location.Y);

Squares[3].Location = new Point(s1.Location.X - Game.Side, s1.Location.Y + Game.Side);

}

else if (Direction == Direction.East)

{

/*

* 2 0 1

* 3

*/

Direction = Direction.South;

Squares[1].Location = new Point(s1.Location.X, s1.Location.Y + Game.Side);

Squares[2].Location = new Point(s1.Location.X, s1.Location.Y - Game.Side);

Squares[3].Location = new Point(s1.Location.X - Game.Side, s1.Location.Y - Game.Side);

}

else if (Direction == Direction.South)

{

/*

* 3 2

* 0

* 1

*/

Direction = Direction.West;

Squares[1].Location = new Point(s1.Location.X - Game.Side, s1.Location.Y);

Squares[2].Location = new Point(s1.Location.X + Game.Side, s1.Location.Y);

Squares[3].Location = new Point(s1.Location.X + Game.Side, s1.Location.Y - Game.Side);

}

else

{

/*

* 3

* 1 0 2

*/

Direction = Direction.North;

Squares[1].Location = new Point(s1.Location.X, s1.Location.Y - Game.Side);

Squares[2].Location = new Point(s1.Location.X, s1.Location.Y + Game.Side);

Squares[3].Location = new Point(s1.Location.X + Game.Side, s1.Location.Y + Game.Side);

}



bool flag = true;

foreach (Square s in Squares)

flag &= Game.IsEmpty(s.Location.Y / Game.Side, s.Location.X / Game.Side);



if (!flag) {

Direction = oldDir;

for (int i = 0; i < oldSquares.Count; i++) Squares[i].Location = new Point(oldSquares[i].Location.X, oldSquares[i].Location.Y);

}

ShowBlock();

}


4.3 有些形状如正方形，旋转后都是一样，无方向可言。长棍子4个方向就只有2种状态，就只需要判断2个方向。到现在为止已经实现方块的移动、叠加、旋转。接下来就是当小方块满行消层的问题。