面试题：What will happen when you attempt to compile and run the following code

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What will happen when you attempt to compile and run the following code
class MyClass{
static String myName="Webs-TV";

MyClass getMyClass(){
System.out.println(myName);
return null;
}
public static void main(String[] args){
System.out.println(new MyClass().getMyClass().myName);
}
}

  
A.Compiler time error
B.runtime error
C.Print "Webs-TV" twice
D.Print "Webs-TV" once

 

 

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答案选C

 

主要考察对静态变量的认识

 

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转帖子内的一回复

 

static 声明的静态属性在不用实例化对象的情况下也能调用。题目中的new MyClass().getMyClass().myName可以解读为匿名对象了MyClass()调用getMyClass()方法返回null相当于MyClass a=null;在调用a的静态属性a.myName。所以答案选C.