AJAX结合PHP代码实现登录
2009-01-02 10:52
567 查看
<script type="text/javascript"><!--
google_ad_client = "pub-4490194096475053";
/* 内容页,300x250,第一屏 */
google_ad_slot = "3685991503";
google_ad_width = 300;
google_ad_height = 250;
// --></script>
<script src="http://pagead2.googlesyndication.com/pagead/show_ads.js" type="text/javascript"></script>
<html>
<head>
<scrīpt language="javascrīpt">
function postRequest(strURL){
var xmlHttp;
if(window.XMLHttpRequest){ // For Mozilla, Safari, ...
var xmlHttp = new XMLHttpRequest();
}
else if(window.ActiveXObject){ // ForInternetExplorer
var xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlHttp.open('POST', strURL, true);
xmlHttp.setRequestHeader('Content-Type', 'application/x-www-form-urlencoded');
xmlHttp.onreadystatechange = function(){
if (xmlHttp.readyState == 4){
updatepage(xmlHttp.responseText);
}
}
xmlHttp.send(strURL);
}
function updatepage(str){
if(str=="yes"){
alert("Welcome User");
}else{
alert("Invalid Login! Please try again!");
}
}
function call_login(){
var username = window.document.f1.username.value;
var password = window.document.f1.password.value;
var url = "login.php?username=" + username + "password=" +password ;
postRequest(url);
}
</scrīpt>
</head>
<body>
<Center>
<form name="f1" ōnSubmit="return call_login();">
<table border="0" bgcolor="#CCCCCC" cellspacing="1" cellpadding="3" width="316">
<tr>
<td align="left" colspan="2"><b><font size="5" color="#000080">Login</font></b></td>
</tr>
<tr>
<td align="right" width="124"><b><font color="#000080">User
Name:</font></b></td>
<td width="177"><input type="text" name="username" id="user" size="20" value="" /></td>
</tr>
<tr>
<td align="right" width="124"><b><font color="#000080">Password:</font></b></td>
<td width="177"><input type="password" name="password" size="20" value="" /></td>
</tr>
<tr>
<td colspan="2" align="center"><input type="button" name="a1" value="Login" ōnClick="call_login()"></td>
</tr>
</table>
</form>
</center>
</body>
</html>
javascript:;" onClick="javascript:tagshow(event, 'PHP');" target="_self">PHP脚本部分login.php:
<?
$username=$_GET["username"];
$password=$_GET["password"];
if($username=="admin" && $password=="admin"){
echo "yes";
}else{
echo "No";
}
?>
google_ad_client = "pub-4490194096475053";
/* 内容页,300x250,第一屏 */
google_ad_slot = "3685991503";
google_ad_width = 300;
google_ad_height = 250;
// --></script>
<script src="http://pagead2.googlesyndication.com/pagead/show_ads.js" type="text/javascript"></script>
<html>
<head>
<scrīpt language="javascrīpt">
function postRequest(strURL){
var xmlHttp;
if(window.XMLHttpRequest){ // For Mozilla, Safari, ...
var xmlHttp = new XMLHttpRequest();
}
else if(window.ActiveXObject){ // ForInternetExplorer
var xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlHttp.open('POST', strURL, true);
xmlHttp.setRequestHeader('Content-Type', 'application/x-www-form-urlencoded');
xmlHttp.onreadystatechange = function(){
if (xmlHttp.readyState == 4){
updatepage(xmlHttp.responseText);
}
}
xmlHttp.send(strURL);
}
function updatepage(str){
if(str=="yes"){
alert("Welcome User");
}else{
alert("Invalid Login! Please try again!");
}
}
function call_login(){
var username = window.document.f1.username.value;
var password = window.document.f1.password.value;
var url = "login.php?username=" + username + "password=" +password ;
postRequest(url);
}
</scrīpt>
</head>
<body>
<Center>
<form name="f1" ōnSubmit="return call_login();">
<table border="0" bgcolor="#CCCCCC" cellspacing="1" cellpadding="3" width="316">
<tr>
<td align="left" colspan="2"><b><font size="5" color="#000080">Login</font></b></td>
</tr>
<tr>
<td align="right" width="124"><b><font color="#000080">User
Name:</font></b></td>
<td width="177"><input type="text" name="username" id="user" size="20" value="" /></td>
</tr>
<tr>
<td align="right" width="124"><b><font color="#000080">Password:</font></b></td>
<td width="177"><input type="password" name="password" size="20" value="" /></td>
</tr>
<tr>
<td colspan="2" align="center"><input type="button" name="a1" value="Login" ōnClick="call_login()"></td>
</tr>
</table>
</form>
</center>
</body>
</html>
javascript:;" onClick="javascript:tagshow(event, 'PHP');" target="_self">PHP脚本部分login.php:
<?
$username=$_GET["username"];
$password=$_GET["password"];
if($username=="admin" && $password=="admin"){
echo "yes";
}else{
echo "No";
}
?>
相关文章推荐
- 简单示例AJAX结合PHP代码实现登录效果代码
- AJAX结合PHP代码实现登录
- 简单示例:AJAX结合PHP代码实现登录
- 简单示例AJAX结合PHP代码实现登录效果代码
- 简单示例AJAX结合PHP代码实现登录效果代码-2
- PHP结合Ajax实现登录验证的Demo
- php和ajax结合实现登录
- php结合Ajax实现异步文件上传的代码实例
- Ajax与PHP结合实现登录验证
- php结合Ajax如何实现异步文件上传的代码实例
- 安卓服务端开发(1) 安卓结合PHP实现连接数据库验证登录功能(附全部代码)
- PHP中运用jQuery的Ajax跨域调用实现代码
- PHP+jQuery+Ajax实现用户登录与退出
- php结合ajax实现手机发红包的案例
- Jquery中的AJax技术结合PHP实现无刷新验证验证码
- 我的第二行php代码之接受get请求连接数据库实现登录验证
- 登录失败次数限制(原生php代码实现)
- php下获取Discuz论坛登录用户名、用户组、用户ID等信息的实现代码
- PHP+jQuery+Ajax实现用户登录与退…
- php+ajax登录跳转登录实现思路