分组统计并且累加的问题

分组统计并且累加的问题
　　问：说有张表 Table (Date, Name, Income).
我想按Name和Date进行月份分组合计Income(不同的姓名和月份要区分出来)，并且增加一个字段Cum，显示各月的Income的累加(当然月份是按升序排列)。Date字段是日期型，格式:mm/dd/yyyy,这个查询怎么写?谢谢!

　　答：如果没猜错的话你的原意，Income
和Cum是两个字段，结果集应该是:

　　Month Name Income/Month Cum

Cum应该显示逐月累加的值，Income/Month显示的是各月的小计值。

Declare @t
Table(Date datetime,name varchar(50),Income int)

Insert @t Select '2006-5-9','A',200

Union all Select '2006-5-19','B',300

Union all Select '2006-6-19','A',300

Union all Select '2006-6-29','B',300

--group by convert(varchar(7) , date , 121)

/*

Select sum(Income) ,convert(varchar(7) , Date , 121) , Name

from @t group by name, convert(varchar(7) , Date
, 121) with rollup

order by convert(varchar(7) , Date , 121)

*/

SELECT convert(varchar(7) ,
Date , 121) as date1,

-- CASE WHEN (GROUPING(
convert(varchar(7) ,Date,121) ) = 1) THEN 'ALL'

--
ELSE convert(varchar(7) , Date
, 121) --ISNULL(convert(varchar(7) , Date , 121), 'UNKNOWN')

--WHEN (GROUPING( convert(varchar(7) ,Date,121) ) <> 1) THEN
convert(varchar(7) ,Date,121)

--
END AS Date2,

CASE WHEN (GROUPING(name) = 1) THEN 'ALL'

ELSE ISNULL(name, 'UNKNOWN')

END AS Name,

SUM(Income) AS QtySum

FROM @t

--where

--date1 is not null

GROUP BY convert(varchar(7) , Date , 121), name WITH ROLLUP

order by convert(varchar(7) , Date , 121) asc

-------

/*

Month
Name
Income/Month
CUM

------ --------------------------------------------------
------------ -----------

200605
A
200
200

200606
A
300
500

200605
B
300
300

200606
B
300
600

*/