如何在PB中进行位操作以及二进制与十进制转换（摘录）

原文：PFC
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本文拟结合PFC中所提供的pfc_n_cst_numerical对象，讲解如何在PB脚本中实现位操作以及二进制与十进制相互转换。
 

（一）编写十进制转换成二进制的函数：
public function string of_binary (long al_decimal);integer  li_remainder

string  ls_binary=''

If IsNull(al_decimal) or al_decimal< 0 Then

    string ls_null

    SetNull(ls_null)

    Return ls_null

End If

If al_decimal = 0 Then

    Return '0'

End If

Do Until al_decimal= 0

    li_remainder = mod(al_decimal, 2)

    al_decimal = al_decimal /2

    ls_binary = string(li_remainder) + ls_binary

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Return ls_binary

end function

 

（二）编写二进制转换成为十进制的函数：
public function long of_decimal (string as_binary);integer li_cnt

long        ll_len

char        lch_char[]

long        ll_decimal=0

If IsNull(as_binary) or Len(as_binary)<=0 then

    long ll_null

    SetNull(ll_null)   

    Return ll_null

End If

ll_len = Len(as_binary)

lch_char = as_binary

For li_cnt = 1 to ll_len

    If (Not lch_char[li_cnt]='1') AND (Not lch_char[li_cnt]='0') Then

        Return -1

    End If

    ll_decimal = ll_decimal + (long(lch_char[li_cnt]) * (2 ^ (ll_len - li_cnt)))

Next

Return ll_decimal

end function

 

（三）编写公用函数以逐位获取BIT位数据：
public function boolean of_getbit (long al_decimal, unsignedinteger ai_bit);Boolean lb_null

If IsNull(al_decimal) or IsNull(ai_bit) then

    SetNull(lb_null)

    Return lb_null

End If

If Int(Mod(al_decimal / (2 ^(ai_bit - 1)), 2)) > 0 Then

    Return True

End If

Return False

end function

 

（四）编写AND与操作函数：
public function long of_bitwiseand (long al_value1, long al_value2);Integer     li_Cnt

Long            ll_Result

Boolean     lb_Value1[32], lb_Value2[32]

If IsNull(al_Value1) Or IsNull(al_Value2) Then

    SetNull(ll_Result)

    Return ll_Result

End If

For li_Cnt = 1 To 32

    lb_Value1[li_Cnt] = of_getbit(al_Value1, li_Cnt)

    lb_Value2[li_Cnt] = of_getbit(al_Value2, li_Cnt)

Next

For li_Cnt = 1 To 32

    If lb_Value1[li_Cnt] And lb_Value2[li_Cnt] Then

        ll_Result = ll_Result + (2^(li_Cnt - 1))

    End If

Next

Return ll_Result

end function

 

（五）编写OR或操作函数：
public function long of_bitwiseor (long al_value1, long al_value2);Integer      li_Cnt

Long            ll_Result

Boolean     lb_Value1[32], lb_Value2[32]

If IsNull(al_Value1) Or IsNull(al_Value2) Then

    SetNull(ll_Result)

    Return ll_Result

End If

For li_Cnt = 1 To 32

    lb_Value1[li_Cnt] = of_getbit(al_Value1, li_Cnt)

    lb_Value2[li_Cnt] = of_getbit(al_Value2, li_Cnt)

Next

For li_Cnt = 1 To 32

    If lb_Value1[li_Cnt] Or lb_Value2[li_Cnt] Then

        ll_Result = ll_Result + (2^(li_Cnt - 1))

    End If

Next

Return ll_Result

end function

 

（六）编写XOR异或操作函数：
public function long of_bitwisexor (long al_value1, long al_value2);Integer     li_Cnt

Long            ll_Result

Boolean     lb_Value1[32], lb_Value2[32]

If IsNull(al_Value1) Or IsNull(al_Value2) Then

    SetNull(ll_Result)

    Return ll_Result

End If

For li_Cnt = 1 To 32

    lb_Value1[li_Cnt] = of_getbit(al_Value1, li_Cnt)

    lb_Value2[li_Cnt] = of_getbit(al_Value2, li_Cnt)

Next

For li_Cnt = 1 To 32

    If (lb_Value1[li_Cnt] And Not lb_Value2[li_Cnt]) Or &

        (Not lb_Value1[li_Cnt] And lb_Value2[li_Cnt]) Then

        ll_Result = ll_Result + (2^(li_Cnt - 1))

    End If

Next

Return ll_Result

end function

 

（七）编写NOT否操作函数：
public function long of_bitwisenot (long al_value);Integer      li_Cnt, li_Count

Long            ll_Result

string      ls_Value, ls_Result

If IsNull(al_Value) Then

    SetNull(ll_Result)

    Return ll_Result

End If

ls_Value = of_binary(al_Value)

li_Cnt = Len(ls_Value)

For li_Count = 1 To li_Cnt

    If Mid(ls_Value, li_Count, 1) = '0' Then

        ls_Result = ls_Result + '1'

    Else

        ls_Result = ls_Result + '0'

    End If

End For

Return of_decimal(ls_Result)   

end function

 

（八）调用上述函数：
//将十进制数10转换为二进制1010
ls_binary = of_binary(10)

//将二进制1010转换为十进制数10
ll_decimal = of_decimal(“1010”)

//执行AND与操作(55 && 44) = 36

ll_ret = of_bitwiseand(55,44) //返回36

//执行NOT否操作(! 55) = 8

ll_ret = of_bitwisenot(55) //返回8

//执行OR或操作(55 || 44) = 63

ll_ret = of_bitwiseor(55,44) //返回63

//执行XOR异或操作(55 XOR 44) = 27

ll_ret = of_bitwisexor(55,44) //返回27

 

 
至此本文结束。