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解决Python logging模块无法正常输出日志的问题

2020-04-08 12:07 615 查看

废话少说,先上代码

File:logger.conf

[formatters]
keys=default

[formatter_default]
format=%(asctime)s - %(name)s - %(levelname)s - %(message)s
class=logging.Formatter

[handlers]
keys=console, error_file

[handler_console]
class=logging.StreamHandler
formatter=default
args=tuple()

[handler_error_file]
class=logging.FileHandler
level=INFO
formatter=default
args=("logger.log", "a")

[loggers]
keys=root

[logger_root]
level=DEBUG
formatter=default
handlers=console,error_file
File:logger.py

#!/bin/env python

import logging
from logging.config import logging

class Test(object):
"""docstring for Test"""
def __init__(self):
logging.config.fileConfig("logger.conf")
self.logger = logging.getLogger(__name__)

def test_func(self):
self.logger.error('test_func function')

class Worker(object):
"""docstring for Worker"""
def __init__(self):
logging.config.fileConfig("logger.conf")
self.logger = logging.getLogger(__name__)

data_logger = logging.getLogger('data')
handler = logging.FileHandler('./data.log')
fmt = logging.Formatter('%(asctime)s|%(message)s')
handler.setFormatter(fmt)
data_logger.addHandler(handler)
data_logger.setLevel(logging.DEBUG)
self.data_logger = data_logger

def test_logger(self):
self.data_logger.error("test_logger function")
instance = Test()
self.data_logger.error("test_logger output")
instance.test_func()

def main():
worker = Worker()
worker.test_logger()

if __name__ == '__main__':
main()

问题一:测试过程中,只能打印出test_logger function一条语句

问题二:明明只在data_logger中打印出语句,但是logger的日志中也出现了相关的日志。

问题一解决方案:

利用python -m pdb logger.py 语句对脚本进行调试发现,在执行instance = Test()语句后,通过print '\n'.join(['%s:%s' % item for item in self.data_logger.__dict__.items()])调试语句看到data_logger的disable属性值由0变成了True,此时logger的对应属性也发生了相同的变化。这种变化导致了logger对象停止记录日志。

参考python logging模块的相关手册发现

“The fileConfig() function takes a default parameter, disable_existing_loggers, which defaults to True for reasons of backward compatibility. This may or may not be what you want, since it will cause any loggers existing before the fileConfig() call to be disabled unless they (or an ancestor) are explicitly named in the configuration.”

的说明,即调用fileconfig()函数会将之前存在的所有logger禁用。

在python 2.7版本该fileConfig()函数添加了一个参数,logging.config.fileConfig(fname, defaults=None, disable_existing_loggers=True),可以显式的将disable_existing_loggers设置为FALSE来避免将原有的logger禁用。

将上述代码中的Test类中的logging.config.fileConfig函数改成logging.config.fileConfig("./logger.conf", disable_existing_loggers=0)就可以解决问题。

不过该代码中由于位于同一程序内,可以直接用logging.getLogger(LOGGOR_NAME)函数引用同一个logger,不用再调用logging.config.fileConfig函数重新加载一遍了。

问题二解决方案:

logger对象有个属性propagate,如果这个属性为True,就会将要输出的信息推送给该logger的所有上级logger,这些上级logger所对应的handlers就会把接收到的信息打印到关联的日志中。logger.conf配置文件中配置了相关的root logger的属性,这个root logger就是默认的logger日志。

修改后的如下:

File:logger.conf

[formatters]
keys=default, data

[formatter_default]
format=%(asctime)s - %(name)s - %(levelname)s - %(message)s
class=logging.Formatter

[formatter_data]
format=%(asctime)s|%(message)s
class=logging.Formatter

[handlers]
keys=console, error_file, data_file

[handler_console]
class=logging.StreamHandler
formatter=default
args=tuple()

[handler_error_file]
class=logging.FileHandler
level=INFO
formatter=default
args=("logger.log", "a")

[handler_data_file]
class=logging.FileHandler
level=INFO
formatter=data
args=("data_new.log", "a")

[loggers]
keys=root, data

[logger_root]
level=DEBUG
handlers=console,error_file

[logger_data]
level=DEBUG
handlers=data_file
qualname=data
propagate=0
File:logger.py

#!/bin/env python

import logging
from logging.config import logging

class Test(object):
"""docstring for Test"""
def __init__(self):
self.logger = logging.getLogger(__name__)

def test_func(self):
self.logger.error('test_func function')

class Worker(object):
"""docstring for Worker"""
def __init__(self):
logging.config.fileConfig("logger.conf")
self.logger = logging.getLogger(__name__)
self.data_logger = logging.getLogger('data')

def test_logger(self):
self.data_logger.error("test_logger function")
instance = Test()
self.data_logger.error("test_logger output")
instance.test_func()

def main():
worker = Worker()
worker.test_logger()

if __name__ == '__main__':
main()

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