numpy聚合运算
2020-04-01 18:35
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文章目录
np.sum()
import numpy as np L = np.random.random(100) """ array([0.10026617, 0.22208392, 0.9249521 , 0.09915353, 0.30470212, 0.51122692, 0.73486797, 0.73507233, 0.64179339, 0.40370626, 0.22776954, 0.66732946, 0.5347043 , 0.30272425, 0.81036623, 0.32578585, 0.03980885, 0.92016591, 0.13026301, 0.38899931, 0.40668397, 0.69827856, 0.88888554, 0.42170014, 0.56613009, 0.73112745, 0.23540702, 0.26560887, 0.4620741 , 0.7627782 , 0.17775585, 0.7898654 , 0.40337386, 0.39557836, 0.06481944, 0.35000668, 0.50073546, 0.41902419, 0.47288019, 0.38332904, 0.84353728, 0.61992307, 0.13020538, 0.59378203, 0.80262377, 0.55329427, 0.11523246, 0.74533632, 0.43952667, 0.44936674, 0.26966049, 0.40762972, 0.67832457, 0.55886082, 0.15315672, 0.74661203, 0.12543229, 0.92515539, 0.60910709, 0.15728999, 0.58760355, 0.3172447 , 0.61663355, 0.25190393, 0.41853258, 0.92064846, 0.85334946, 0.18448556, 0.10266699, 0.96811099, 0.02703382, 0.22325344, 0.8907696 , 0.80430375, 0.52975917, 0.42825026, 0.96883465, 0.23110711, 0.25769511, 0.1812734 , 0.3730161 , 0.6634779 , 0.35301686, 0.8910128 , 0.3907653 , 0.3378278 , 0.94125455, 0.88212927, 0.40530354, 0.66303183, 0.4412877 , 0.97359631, 0.81597928, 0.79335775, 0.35993264, 0.82023989, 0.32684658, 0.30465004, 0.78031076, 0.1489848 ]) """
sum(L) #49.77532270487708 np.sum(L) #49.77532270487708
性能比较:
big_array = np.random.rand(1000000) %timeit sum(big_array) %timeit np.sum(big_array)
129 ms ± 6.62 ms per loop (mean ± std. dev. of 7 runs, 10 loops each) 889 µs ± 112 µs per loop (mean ± std. dev. of 7 runs, 1000 loops each)
np.min();np.max()
np.min(big_array) #4.245650752077168e-07 np.max(big_array) #0.9999984487634189 big_array.min() #4.245650752077168e-07 big_array.max() #0.9999984487634189 big_array.sum() #500120.87579514383
二维数组应用
x = np.arange(16).reshape(4,-1) x """ array([[ 0, 1, 2, 3], [ 4, 5, 6, 7], [ 8, 9, 10, 11], [12, 13, 14, 15]]) """ np.sum(x,axis=0)#沿行进行求和 #array([24, 28, 32, 36]) np.sum(x,asix=1)#沿列进行求和 #array([6,22,38,54]) np.prod(x)#每个元素相乘 #0 np.prod(x+1) #2004189184 np.mean(x)#均值 #7.5 np.median(x)#中位数 #7.5
均值与中位数
v = np.array([1,1,2,2,10]) np.mean(v) #3.2 np.median(v) #2.0
均值不能很好的反映数据的平均水平
np.percentile()
np.percentile(big_array,q=50) #百分位点 50%的分位数,是big_array的中位数 np.median(big_array) #得到的效果一样 #几个重要的分位数 for i in [0,25,50,75,100]: print(np.percentile(big_array,q=i))
np.var()求方差;np.std()求标准差
np.var(big_array) #方差0.08329112637157116 np.std(big_array) #标准差
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