查找所有员工自入职以来的薪水涨幅情况，给出员工编号emp_no以及其对应的薪水涨幅growth，并按照growth进行升序

版权声明：matthew_Leung https://blog.csdn.net/mathew_leung/article/details/83870728

题目描述

查找所有员工自入职以来的薪水涨幅情况，给出员工编号emp_no以及其对应的薪水涨幅growth，并按照growth进行升序
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));

输入描述:

无

输出描述:

emp_no	growth
10011	0
省略	省略
10010	54496
10004	34003

示例1

输入

复制

无

输出

复制

无

[code]--查找所有员工自入职以来的薪水涨幅情况，
--给出员工编号emp_no以及其对应的薪水涨幅growth，并按照growth进行升序
SELECT
sCurrent.emp_no,
( sCurrent.salary - sStart.salary ) AS growth
FROM
(
SELECT
s.emp_no,
s.salary
FROM
employees e,
salaries s
WHERE
e.emp_no = s.emp_no
AND s.to_date = '9999-01-01'
) AS sCurrent,
(
SELECT
s.emp_no,
s.salary
FROM
employees e,
salaries s
WHERE
e.emp_no = s.emp_no
AND s.from_date = e.hire_date
) AS sStart
WHERE
sCurrent.emp_no = sStart.emp_no
ORDER BY
growth;
--第二种方法
SELECT
a.emp_no,
( b.salary - c.salary ) AS growth
FROM
employees AS a
INNER JOIN salaries AS b ON a.emp_no = b.emp_no
AND b.to_date = '9999-01-01'
INNER JOIN salaries AS c ON a.emp_no = c.emp_no
AND a.hire_date = c.from_date
ORDER BY
growth ASC;