#1197 : Give My Text Back

时间限制:10000ms单点时限:1000ms内存限制:256MB

描述

To prepare for the English exam Little Ho collected many digital reading materials. Unfortunately the materials are messed up by a malware.It is known that the original text contains only English letters (a-zA-Z), spaces, commas, periods and newlines, conforming to the following format:1. Each sentence contains at least one word, begins with a letter and ends with a period.2. In a sentence the only capitalized letter is the first letter.3. In a sentence the words are separated by a single space or a comma and a space.4. The sentences are separated by a single space or a single newline.It is also known the malware changes the text in the following ways:1. Changing the cases of letters.2. Adding spaces between words and punctuations.Given the messed text, can you help Little Ho restore the original text?

输入

A string containing no more than 8192 English letters (a-zA-Z), spaces, commas, periods and newlines which is the messed text.

输出

The original text.样例输入

my Name  is Little   Hi.
His   name IS Little ho  ,  We are   friends.

样例输出

My name is little hi.
His name is little ho, we are friends.

 这道题虽然只是个简单的模拟就可以。但是弄的我很惨，发下来，做个几年教训，以后遇到细节的希望能写好。
先把所有字母变成小写，空格去掉，在进行输出，增加大写字母的操作。
代码：#include <bits/stdc++.h>

using namespace std;
/*
97 122
65 90
*/
int main()
{
string a;
string b;
while(getline(cin,a))
{
b="";
int l=a.size();
for(int i=0;i<l;i++)
{
if(a[i]>='A'&&a[i]<='Z')
{
b+=(a[i]+32);
}
else
{
if(a[i]==' '&&a[i+1]==' ')continue;
if(a[i]==' '&&a[i+1]==',')continue;
if(a[i]==' '&&a[i+1]=='.')continue;
if(a[i]==','&&a[i+1]!=' ')
{
b+=a[i];
b+=' ';
continue;
}
if(a[i]=='.'&&a[i+1]!=' ')
{
b+=a[i];
b+=' ';
continue;
}
b+=a[i];
}
}
int le=b.size();
int ju=1;
for(int i=0;i<le;i++)
{
if(b[i]=='.')
{
ju=1;
continue;
}
if(ju)
{
if(b[i]>='a'&&b[i]<='z')
{
b[i]=b[i]-32;
ju=0;
}
}

}
cout<<b<<endl;

}
return 0;
}