lintcode 41.最大子数组
2018-03-14 14:29
375 查看
class Solution:
def maxSubArray(self, nums):
if nums is None or len(nums) == 0:
return 0
maxSum = nums[0]
minSum = 0
sum = 0
for num in nums:
sum += num
if sum - minSum > maxSum:
maxSum = sum - minSum
if sum < minSum:
minSum = sum
return maxSum
*************************
搞不懂
def maxSubArray(self, nums):
if nums is None or len(nums) == 0:
return 0
maxSum = nums[0]
minSum = 0
sum = 0
for num in nums:
sum += num
if sum - minSum > maxSum:
maxSum = sum - minSum
if sum < minSum:
minSum = sum
return maxSum
*************************
搞不懂
相关文章推荐
- LintCode-41. 最大子数组
- LintCode【简单】41. 最大子数组 。代码及思路
- Lintcode 41.最大子数组
- python_lintcode_简单题 _44最小子数组_41最大子数组
- lintcode--41. 最大子数组
- LintCode 最大子数组(dp)
- LintCode-41.最大子数组
- lintcode 最大子数组(Maximum Subarray )(Java)
- LintCode 第41题 最大子数组
- lintcode--45. 最大子数组差
- lintcode---43. 最大子数组 III
- [置顶] lintcode(617)最大平均值子数组
- LintCode 41. 最大子数组
- LintCode求最大平均值子数组
- LintCode_041_最大子数组
- 41.最大子数组
- LintCode_041_最大子数组
- lintcode 最大子数组III
- [LintCode]41.最大子数组
- <LeetCode> 题41:最大子数组