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4000 mysql分组排序取最大、最小、最新、前N条记录

2018-03-08 11:11 495 查看
先看一下本示例中需要使用到的数据创建表并插入数据:
create table tb(name varchar(10),val int,memo varchar(20))
insert into tb values('a',    2,   'a2')
insert into tb values('a',    1,   'a1')
insert into tb values('a',    3,   'a3')
insert into tb values('b',    1,   'b1')
insert into tb values('b',    3,   'b3')
insert into tb values('b',    2,   'b2')
insert into tb values('b',    4,   'b4')
insert into tb values('b',    5,   'b5')
数据表如下:
namevalmemo
a2a2
a1a1
a3a3
b1b1
b3b3
b2b2
b4b4
b5b5
 

按name分组取val最大的值所在行的数据

方法一:
select a.* from tb a where val = (select max(val) from tb where name = a.name) order by a.name
方法二:
select a.* from tb a where not exists(select 1 from tb where name = a.name and val > a.val)
方法三:
select a.* from tb a,(select name,max(val) val from tb group by name) b where a.name = b.name and a.val = b.val order by a.name
方法四:
select a.* from tb a inner join (select name , max(val) val from tb group by name) b on a.name = b.name and a.val = b.val order by
方法五:
select a.* from tb a where 1 > (select count(*) from tb where name = a.name and val > a.val ) order by a.name
以上五种方法运行的结果均为如下所示:
namevalmemo
a3a3
b5b5
小编推荐使用第一、第三、第四钟方法,结果显示第1,3,4种方法效率相同,第2,5种方法效率差些。

按name分组取val最小的值所在行的数据

方法一:
select a.* from tb a where val = (select min(val) from tb where name = a.name) order by a.name
方法二:
select a.* from tb a where not exists(select 1 from tb where name = a.name and val < a.val)
方法三:
select a.* from tb a,(select name,min(val) val from tb group by name) b where a.name = b.name and a.val = b.val order by a.name
方法四:
select a.* from tb a inner join (select name , min(val) val from tb group by name) b on a.name = b.name and a.val = b.val order by a.name
方法五:
select a.* from tb a where 1 > (select count(*) from tb where name = a.name and val < a.val) order by a.name
以上五种方法运行的结果均为如下所示:
namevalmemo
a1a1
b1b1
 

按name分组取第一次出现的行所在的数据 

sql如下:
select a.* from tb a where val = (select top 1 val from tb where name = a.name) order by a.name
结果如下:
namevalmemo
a2a2
b1b1
 

按name分组随机取一条数据

sql如下:
select a.* from tb a where val = (select top 1 val from tb where name = a.name order by newid()) order by a.name
结果如下:
namevalmemo
a1a1
b3b3
 

按name分组取最小的两个(N个)val

第一种方法:
select a.* from tb a where 2 > (select count(*) from tb where name = a.name and val < a.val ) order by a.name,a.val
第二种方法:
select a.* from tb a where val in (select top 2 val from tb where name=a.name order by val) order by a.name,a.val
第三种方法:
select a.* from tb a where exists (select count(*) from tb where name = a.name and val < a.val having Count(*) < 2) order by a.name
结果如下:
namevalmemo
a1a1
a2a2
b1b1
b2b2
 

按name分组取最大的两个(N个)val

第一种方法:
select a.* from tb a where 2 > (select count(*) from tb where name = a.name and val > a.val ) order by a.name,a.val
第二种方法:
select a.* from tb a where val in (select top 2 val from tb where name=a.name order by val desc) order by a.name,a.val
第三种方法:
select a.* from tb a where exists (select count(*) from tb where name = a.name and val > a.val having Count(*) < 2) order by a.name
结果如下:
namevalmemo
a3a3
a2a2
b5b5
b4b4
原文地址:http://www.manongjc.com/article/1082.html
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