771. Jewels and Stones。
2018-02-20 17:08
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You’re given strings J representing the types of stones that are jewels, and S representing the stones you have. Each character in S is a type of stone you have. You want to know how many of the stones you have are also jewels.
The letters in J are guaranteed distinct, and all characters in J and S are letters. Letters are case sensitive, so “a” is considered a different type of stone from “A”.
Example 1:
Input: J = “aA”, S = “aAAbbbb”
Output: 3
Example 2:
Input: J = “z”, S = “ZZ”
Output: 0
J是宝石类型,S是自己拥有的,需要看看自己手中的石头有多少是宝石。
查找一下就行了。
The letters in J are guaranteed distinct, and all characters in J and S are letters. Letters are case sensitive, so “a” is considered a different type of stone from “A”.
Example 1:
Input: J = “aA”, S = “aAAbbbb”
Output: 3
Example 2:
Input: J = “z”, S = “ZZ”
Output: 0
J是宝石类型,S是自己拥有的,需要看看自己手中的石头有多少是宝石。
查找一下就行了。
class Solution { public: int numJewelsInStones(string J, string S) { int count = 0; for(auto s : S) { if(J.find(s)!=-1) { count++; } } return count; } };
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