PATB1028.人口普查（20）

题目链接：点击打开链接

知识点笔记：

AC代码：

#include <cstdio>

struct person{
char name[10];
int y,m,d;
}youngest,oldest,left,right,temp;

bool lessEqu(person a,person b){
if(a.y!=b.y) return a.y<=b.y;
else if(a.m!=b.m) return a.m<=b.m;
else  return a.d<=b.d;
}

void init(){
right.y = oldest.y=2014;
left.y = youngest.y = 1814;
right.m=left.m=oldest.m=youngest.m=9;
right.d=left.d=oldest.d=youngest.d=6;
}
int main() {

int n;
int count=0;
scanf("%d",&n);
init();
for(int i=0;i<n;i++){

scanf("%s %d/%d/%d",temp.name,&temp.y,&temp.m,&temp.d);

if(lessEqu(temp,right)&&lessEqu(left,temp)){
count++;
if(lessEqu(temp,oldest))
oldest=temp;
if(lessEqu(youngest,temp))
youngest=temp;

}
}

if(count) printf("%d %s %s\n",count,oldest.name,youngest.name);
else printf("0\n");

return 0;
}