<easy>LeetCode Problem -- 674. Longest Continuous Increasing Subsequence

描述：Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarray).

Example 1:

Input: [1,3,5,4,7]

Output: 3

Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3.

Even though [1,3,5,7] is also an increasing subsequence, it’s not a continuous one where 5 and 7 are separated by 4.

Example 2:

Input: [2,2,2,2,2]

Output: 1

Explanation: The longest continuous increasing subsequence is [2], its length is 1.

分析：题目中给出一个数组，要求找到这个数组的最大连续递增子串，并输出他的长度。

思路一：通过比较前后两个值的差来确定子串的状态，如果为正则为递增子串，给计数器加一，否则将计数器记为0。

class Solution {
public:
int findLengthOfLCIS(vector<int>& nums) {
if (nums.empty()) return 0;
int begin = 0;
int max_len = 1;
int temp = 1;
for (int i = 1; i < nums.size(); i++) {
if (nums[i] - nums[begin] > 0) {
temp++;
max_len = max(max_len, temp);
} else {
temp = 1;
}
begin++;
}
return max_len;
}
};