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tf.reduce_mean

2018-02-04 17:38 453 查看
reduce_mean(
    input_tensor,
    axis=None,
    keepdims=None,
    name=None,
    reduction_indices=None,
    keep_dims=None
)

Defined in
tensorflow/python/ops/math_ops.py
.

See the guide:
Math > Reduction

Computes the mean of elements across dimensions of a tensor. (deprecated arguments)

SOME ARGUMENTS ARE DEPRECATED. They will be removed in a future version.Instructions for updating:keep_dims is deprecated, use keepdims instead

Reduces
input_tensor
along the dimensions given in
axis
.Unless
keepdims
is true, the rank of the tensor is reduced by 1 for eachentry in
axis
. If
keepdims
is true, the reduced dimensionsare retained with length 1.

If
axis
has no entries, all dimensions are reduced, and atensor with a single element is returned.

For example:

x = tf.constant([[1., 1.], [2., 2.]])
tf.reduce_mean(x)  # 1.5
tf.reduce_mean(x, 0)  # [1.5, 1.5]
tf.reduce_mean(x, 1)  # [1.,  2.]

Args:

input_tensor
: The tensor to reduce. Should have numeric type.
axis
: The dimensions to reduce. If
None
(the default), reduces all dimensions. Must be in the range
[-rank(input_tensor), rank(input_tensor))
.
keepdims
: If true, retains reduced dimensions with length 1.
name
: A name for the operation (optional).
reduction_indices
: The old (deprecated) name for axis.
keep_dims
: Deprecated alias for
keepdims
.

Returns:

The reduced tensor.

Numpy Compatibility

Equivalent to np.mean

Please note that
np.mean
has a
dtype
parameter that could be used tospecify the output type. By default this is
dtype=float64
. On the otherhand,
tf.reduce_mean
has an aggressive type inference from
input_tensor
,for example:

x = tf.constant([1, 0, 1, 0])
tf.reduce_mean(x)  # 0
y = tf.constant([1., 0., 1., 0.])
tf.reduce_mean(y)  # 0.5


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上次更新日期:一月 27, 2018
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