[LeetCode By Python]58. Length of Last Word
2018-01-28 20:51
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题目：
Given a string s consists of upper/lower-case alphabets and empty space characters
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
Example:
我用的字符串内置函数，只有两行代码，然而我发现提交后，虽然正确但时间花费太多
代码＋测试：
class Solution(object):
def lengthOfLastWord(self, s):
"""
:type s: str
:rtype: int
"""
lists = s.rstrip().split(' ')
return len(lists[-1])
a = Solution()
print a.lengthOfLastWord(" ")
Given a string s consists of upper/lower-case alphabets and empty space characters
' ', return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
Example:
Input: "Hello World" Output: 5
我用的字符串内置函数，只有两行代码，然而我发现提交后，虽然正确但时间花费太多
代码＋测试：
class Solution(object):
def lengthOfLastWord(self, s):
"""
:type s: str
:rtype: int
"""
lists = s.rstrip().split(' ')
return len(lists[-1])
a = Solution()
print a.lengthOfLastWord(" ")
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