[LeetCode]Remove Element@python

Given an array and a value, remove all instances of that value
in-place and return the new length.

Do not allocate extra space for another array, you must do this by modifying the input arrayin-place with O(1) extra memory.

The order of elements can be changed. It doesn't matter what you leave beyond the new length.

Example:

Given nums = [3,2,2,3], val = 3,

Your function should return length = 2, with the first two elements of nums being 2.

class Solution(object):
def removeElement(self, nums, val):
"""
:type nums: List[int]
:type val: int
:rtype: int
"""
if not nums:
return 0

j = 0
for i in range(len(nums)):
if val != nums[i]:
nums[j] = nums[i]
j += 1

return j