您的位置:首页 > 其它

简单的web备份脚本

2018-01-16 09:23 281 查看
#!/bin/bash
DATE=`date +%Y-%m-%d`
day=5
#backsource=/data1/webdata
backsource=/data1/webdata
backuppath=/data1/backup/WebBackup
webs="web1 web2 web3"
if [ ! -d $backuppath ]; then mkdir -p $backuppath
fi
cd $backuppath

backupname=Web_Backup_$DATE
for web in $webs;
do
tar -C $backsource  -zcvf $web.tar.gz $web
if [ "$?" == "0" ]
then
echo "$DATE  $web  backuped" >> $backuppath/backupweb.log
else
echo "$DATE  $web  backup failed" >> $backuppath/backupweb.log
exit 0
fi
done
tar -jcvf $backupname.tar.bz2  *.tar.gz
if [ "$?" == "0" ]
then
echo "$DATE Packaging complete" >> $backuppath/backupweb.log
else
echo "$DATE Packaging failed" >> $backuppath/backupweb.log
exit 0
fi
rm -f  *.tar.gz
delname=Web_Backup_$(date -d "$day day ago" +%Y-%m-%d).tar.bz2
rm -f $delname
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: