您的位置:首页 > 编程语言 > Python开发

python-------------自定义str转换成int的函数

2017-12-13 14:45 344 查看
# -*- coding: utf-8 -*-
# Author	:Gogh
# @Time		:2017/12/7 15:39
# @Email	:361910002@qq.com
def str2int(s):
def fn(x, y):
return x * 10 + y
def char(s):
return {'0': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9}[s]
return reduce(fn, map(char, s))
print (str2int('545455'))
# lambda函数进一步简化
def char2num(s):
return {'0': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9}[s]
def str2int(s):
return reduce(lambda x, y: x*10+y, map(char2num, s))
print (str2int('1211212'))
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: