linux两个线程交替打印数字

#include<stdio.h>
#include<unistd.h>
#include<stdlib.h>
#include<pthread.h>

#define COUNT 10
static  int   i = 1;

pthread_mutex_t mutex = PTHREAD_MUTEX_INITIALIZER;
pthread_cond_t  even  = PTHREAD_COND_INITIALIZER;
pthread_cond_t  uneven = PTHREAD_COND_INITIALIZER;

//1 3 5 7 9
void* funA(void *arg)
{
while(i <= COUNT)
{
pthread_mutex_lock(&mutex);
if(i % 2 != 0)
{
printf("funA : %d\n",i);
++i;
pthread_cond_signal(&uneven);
}
else
pthread_cond_wait(&even, &mutex);
pthread_mutex_unlock(&mutex);
}
}
//2 4 6 8 10
void* funB(void *arg)
{
while(i <= COUNT)
{
pthread_mutex_lock(&mutex);
if(i % 2 == 0)
{
printf("funB : %d\n",i);
++i;
pthread_cond_signal(&even);
}
else
pthread_cond_wait(&uneven, &mutex);
pthread_mutex_unlock(&mutex);
}
}

int main()
{
pthread_t tid1, tid2;
pthread_create(&tid1, NULL, funA, NULL);
pthread_create(&tid2, NULL, funB, NULL);

pthread_join(tid1, NULL);
pthread_join(tid2, NULL);
return 0;
}