3.9 All in All UVa 10340
2017-11-30 10:06
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题目比较水,不过数据真是坑,那么大
#include <stdio.h>
#include <string.h>
char s[1000000] = {'\0'}, t[1000000] = {'\0'};//1000,3000,10000。。。为啥要这么大才够
int main()
{
while( scanf("%s", s) != EOF )
{
scanf("%s", t);
int i, j = 0;
long long k = 0, lens = strlen(s), lent = strlen(t);
for(i = 0; j < lent&&i < lens; i++)
for(;j < lent;)
{
if(s[i] == t[j]) {++j;k++;break;}
else j++;
}
if(k == lens)
printf("Yes\n");
else
printf("No\n");
}
return 0;
}
#include <stdio.h>
#include <string.h>
char s[1000000] = {'\0'}, t[1000000] = {'\0'};//1000,3000,10000。。。为啥要这么大才够
int main()
{
while( scanf("%s", s) != EOF )
{
scanf("%s", t);
int i, j = 0;
long long k = 0, lens = strlen(s), lent = strlen(t);
for(i = 0; j < lent&&i < lens; i++)
for(;j < lent;)
{
if(s[i] == t[j]) {++j;k++;break;}
else j++;
}
if(k == lens)
printf("Yes\n");
else
printf("No\n");
}
return 0;
}
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