203-Remove Linked List Elements
2017-11-03 13:27
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难度:easy
类别:linked list
Example
Given: 1 –> 2 –> 6 –> 3 –> 4 –> 5 –> 6, val = 6
Return: 1 –> 2 –> 3 –> 4 –> 5
因为while循环中是head->next,所以最后要对第一节点进行判断。
整体思路很简单,实现也不难。
类别:linked list
1.题目描述
Remove all elements from a linked list of integers that have value val.Example
Given: 1 –> 2 –> 6 –> 3 –> 4 –> 5 –> 6, val = 6
Return: 1 –> 2 –> 3 –> 4 –> 5
2.算法分析
遍历链表,比较head->next的值与val是否相等,如果相等的话,将其删除,并且head->next = head->next->next.因为while循环中是head->next,所以最后要对第一节点进行判断。
整体思路很简单,实现也不难。
3.代码实现
ListNode* removeElements(ListNode* head, int val) { if (head == NULL) return head; if (head->next == NULL && head->val == val) return NULL; if (head->next == NULL && head->val != val) return head; ListNode* result = head; ListNode* temp = NULL; while (head->next != NULL) { if (head->next->val == val) { temp = head->next; head->next = temp->next; delete temp; } else { head = head->next; } } // 最后的时候再判断第一节点,看是不是需要删除 if (result->val == val) { result = result->next; } return result; }
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