Leetcode-Remove Duplicates from Sorted List II(二级指针)
2017-11-02 16:47
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Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.
For example,
Given
Given
Seen this question in a real interview before?
Yes
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode *deleteDuplicates(ListNode *head) {
ListNode **runner = &head;
if(!head || !head->next)return head;
while(*runner)
{
if((*runner)->next && (*runner)->next->val == (*runner)->val)
{
ListNode *temp = *runner;
while(temp && (*runner)->val == temp->val)
temp = temp->next;
*runner = temp;
}
else
runner = &((*runner)->next);
}
return head;
}
};
For example,
Given
1->2->3->3->4->4->5, return
1->2->5.
Given
1->1->1->2->3, return
2->3.
Seen this question in a real interview before?
Yes
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode *deleteDuplicates(ListNode *head) {
ListNode **runner = &head;
if(!head || !head->next)return head;
while(*runner)
{
if((*runner)->next && (*runner)->next->val == (*runner)->val)
{
ListNode *temp = *runner;
while(temp && (*runner)->val == temp->val)
temp = temp->next;
*runner = temp;
}
else
runner = &((*runner)->next);
}
return head;
}
};
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