您的位置:首页 > 编程语言 > Python开发

冒泡排序:python

2017-11-01 09:46 183 查看
# -*- coding: utf_8  -*-
print(__doc__)
dic = {}
with open('G:/py_proj/test/flask.txt') as f:
for char in   f.read().replace(' ',''):
if char in dic:
dic[char] += 1
else:
dic[char] = 1
# print(dic)
rev_list = list(dic.items())
length = len(rev_list)
# 冒泡排序
for i in range(length-1):
for j in range(length-i-1):  #j为下标识
if rev_list[j][1] > rev_list[j+1][1]:
rev_list[j],rev_list[j+1] = rev_list[j+1],rev_list[j]
print(rev_list)
for char ,c  in sorted(rev_list,key= lambda x:x[1],reverse= True):
print('%s count is %d' %(char,c))
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: