android唯一设备标识、设备号、设备ID的获取方法

##如何获取Android设备唯一ID？

###问题 每一个android设备都有唯一ID吗？如果有？怎么用java最简单取得呢？

###回答1（最佳）

如何取得android唯一码？

好处：

1.不需要特定权限.

2.在99.5% Android装置（包括root过的）上，即API => 9，保证唯一性.

3.重装app之后仍能取得相同唯一值.

伪代码：

if API => 9/10: (99.5% of devices)

return unique ID containing serial id (rooted devices may be different)

else

return unique ID of build information (may overlap data - API < 9)

代码:

/**
* Return pseudo unique ID
* @return ID
*/
@SuppressLint("NewApi")
public static String getUniquePsuedoID() {
// If all else fails, if the user does have lower than API 9 (lower
// than Gingerbread), has reset their device or 'Secure.ANDROID_ID'
// returns 'null', then simply the ID returned will be solely based
// off their Android device information. This is where the collisions
// can happen.
// Thanks http://www.pocketmagic.net/?p=1662! // Try not to use DISPLAY, HOST or ID - these items could change.
// If there are collisions, there will be overlapping data

String[] supportedABIArray;
if (Build.VERSION.SDK_INT >= 21) {
supportedABIArray = Build.SUPPORTED_ABIS;
} else {
supportedABIArray = new String[] {Build.CPU_ABI};
}

String supportedABIs = "";
try {
for (String s : supportedABIArray) {
supportedABIs += s;
}
} catch (Exception e) {
supportedABIs = "";
}

String m_szDevIDShort = "35";
if (null != Build.BOARD) m_szDevIDShort += (Build.BOARD.length() % 10);
if (null != Build.BRAND) m_szDevIDShort += (Build.BRAND.length() % 10);
if (null != supportedABIs) m_szDevIDShort += (supportedABIs.length() % 10);
if (null != Build.DEVICE) m_szDevIDShort += (Build.DEVICE.length() % 10);
if (null != Build.MANUFACTURER) m_szDevIDShort += (Build.MANUFACTURER.length() % 10);
if (null != Build.MODEL) m_szDevIDShort += (Build.MODEL.length() % 10);
if (null != Build.PRODUCT) m_szDevIDShort += (Build.PRODUCT.length() % 10);// Thanks to @Roman SL!
// http://stackoverflow.com/a/4789483/950427 // Only devices with API >= 9 have android.os.Build.SERIAL
// http://developer.android.com/reference/android/os/Build.html#SERIAL // If a user upgrades software or roots their device, there will be a duplicate entry
String serial = null;
try {
serial = android.os.Build.class.getField("SERIAL").get(null).toString();

// Go ahead and return the serial for api => 9
return new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString();
} catch (Exception exception) {
// serial = "serial"; // constant value
serial = "" + Calendar.getInstance().getTimeInMillis(); // variable value
}

// Thanks @Joe!
// http://stackoverflow.com/a/2853253/950427 // Finally, combine the values we have found by using the UUID class to create a unique
// identifier
return new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString();
}

###回答2 好处：

1.不需要特定权限.

2.在100% Android装置（包括root过的）上，保证唯一性.

坏处

1.重装app之后不能取得相同唯一值.

private static String uniqueID = null;
private static final String PREF_UNIQUE_ID = "PREF_UNIQUE_ID";

public synchronized static String id(Context context) {
if (uniqueID == null) {
SharedPreferences sharedPrefs = context.getSharedPreferences(
PREF_UNIQUE_ID, Context.MODE_PRIVATE);
uniqueID = sharedPrefs.getString(PREF_UNIQUE_ID, null);
if (uniqueID == null) {
uniqueID = UUID.randomUUID().toString();
Editor editor = sharedPrefs.edit();
editor.putString(PREF_UNIQUE_ID, uniqueID);
editor.commit();
}
}
return uniqueID;
}

###回答3（需要有电话卡）

好处： 1.重装app之后仍能取得相同唯一值.

代码：

final TelephonyManager tm = (TelephonyManager) getBaseContext().getSystemService(Context.TELEPHONY_SERVICE);
final String tmDevice, tmSerial, androidId;
tmDevice = "" + tm.getDeviceId();
tmSerial = "" + tm.getSimSerialNumber();
androidId = "" + android.provider.Settings.Secure.getString(getContentResolver(), android.provider.Settings.Secure.ANDROID_ID);
UUID deviceUuid = new UUID(androidId.hashCode(), ((long)tmDevice.hashCode() << 32) | tmSerial.hashCode());
String deviceId = deviceUuid.toString();

谨记：要取得以下权限

<uses-permission android:name="android.permission.READ_PHONE_STATE" />