2017 ACM/ICPC Asia Regional Shenyang Online card card card
2017-09-19 11:03
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题意:看后面也应该知道是什么意思了
解法:
我们设置l,r,符合条件就是l=起始点,r=当前点,不符合l=i+1
学习了一下FASTIO
#include <iostream> #include <algorithm> #include <set> #include <string> #include <vector> #include <queue> #include <map> #include <stack> #include <list> #include <iomanip> #include <functional> #include <sstream> #include <cstdio> #include <cstring> #include <cmath> #include <cctype> //#define read read() #define edl putchar('\n') #define ll long long #define clr(a,b) memset(a,b,sizeof a) #define rep(i,m,n) for(int i=m ; i<=n ; i++) #define fep(i,n) for(int i=0 ; i<n ; i++) //inline int read{ int x=0;char c=getchar();while(c<'0' || c>'9')c=getchar();while(c>='0' && c<='9'){ x=x*10+c-'0';c=getchar(); }return x;} namespace FastIO { const int SIZE = 1 << 16; char buf[SIZE], obuf[SIZE], str[60]; int bi = SIZE, bn = SIZE, opt; int read(char *s) { while (bn) { for (; bi < bn && buf[bi] <= ' '; bi++); if (bi < bn) break; bn = fread(buf, 1, SIZE, stdin); bi = 0; } int sn = 0; while (bn) { for (; bi < bn && buf[bi] > ' '; bi++) s[sn++] = buf[bi]; if (bi < bn) break; bn = fread(buf, 1, SIZE, stdin); bi = 0; } s[sn] = 0; return sn; } bool read(int& x) { int n = read(str), bf; if (!n) return 0; int i = 0; if (str[i] == '-') bf = -1, i++; else bf = 1; for (x = 0; i < n; i++) x = x * 10 + str[i] - '0'; if (bf < 0) x = -x; return 1; } }; #define read(x) FastIO::read(x) using namespace std; int X[1234567*2],Y[1234567*2]; const int maxn = 1007; int n, m, mp[maxn][maxn], link[maxn]; bool vis[maxn]; int main() { while(read(n)) { for(int i=1;i<=n;i++){ read(X[i]); X[n+i]=X[i]; } for(int i=1;i<=n;i++){ read(Y[i]); Y[i]=X[i]-Y[i]; Y[i+n]=Y[i]; } int sum=0; int ans=0; int index=1; int r=1; int St; int Max=-((1<<31)-1); for(int i=1;i<=2*n;i++){ sum+=X[i]; ans+=Y[i]; if(sum>Max){ Max=sum; St=index; r=i; } if(ans<0){ index=i+1; sum=0; ans=0; if(index>n+1){ break; } } } printf("%d\n",St-1); } return 0; }
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