674. Longest Continuous Increasing Subsequence
2017-09-11 21:30
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Given an unsorted array of integers, find the length of longest
subsequence.
Example 1:
Example 2:
Note: Length of the array will not exceed 10,000.
class Solution {
public int findLengthOfLCIS(int[] nums) {
if (nums.length == 0)
return 0;
int re = 1;
int cur = 1;
for (int i = 1; i < nums.length; ++i) {
if (nums[i] > nums[i - 1])
cur++;
else {
re = Math.max(re, cur);
cur = 1;
}
}
return Math.max(re, cur);
}
}
continuousincreasing
subsequence.
Example 1:
Input: [1,3,5,4,7] Output: 3 Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4.
Example 2:
Input: [2,2,2,2,2] Output: 1 Explanation: The longest continuous increasing subsequence is [2], its length is 1.
Note: Length of the array will not exceed 10,000.
class Solution {
public int findLengthOfLCIS(int[] nums) {
if (nums.length == 0)
return 0;
int re = 1;
int cur = 1;
for (int i = 1; i < nums.length; ++i) {
if (nums[i] > nums[i - 1])
cur++;
else {
re = Math.max(re, cur);
cur = 1;
}
}
return Math.max(re, cur);
}
}
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