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BootStrap给table表格的每一行添加一个按钮事件

2017-09-07 11:47 866 查看

1.在列属性中加入事件

{
title:'数据量序号',
field:'sjid'
// hidden:true
},{
field: 'operate',
title: '操作',
width: '80px',
events: operateEvents,
formatter: operateFormatter
}

2.写一个函数

function operateFormatter(value, row, index) {
return [
'<input type="submit" value="上传" class="RoleOfedit btn btn-primary btn-sm"   data-toggle="modal" style="display:inline">',
].join('');
}

3.记得这个写在表格的前面

window.operateEvents = {
'click .RoleOfedit': function (e, value, row, index) {
alert(row.qxxh);
$("#upload").modal('show');
}
};

4.点击“弹出模态框”

<div class="modal fade" id="upload" tabindex="-1" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true">
<form action="http://localhost:8080/GD/UploadAction_execute.action" method="post" enctype="multipart/form-data" name="uploadfile">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal" aria-hidden="true">×</button>
<h4 class="modal-title" id="myModalLabelfile">上传文件</h4>
</div>
<div class="modal-body">
<input type="file" name="my" id="file" value="浏览" style="display: none;"
onchange="document.uploadfile.filePath.value=this.value"/>
<input type="text" name="filePath" id="filePath"/>
<input type="button" value="浏览..." onclick="document.uploadfile.my.click()"/><br>
<input type="submit" value="上传" id="shangchuan">
</div>
<div class="modal-footer"> <button type="button" class="btn btn-default" data-dismiss="modal">关闭</button>
</div>
</div>
<!-- /.modal-content -->
</div>
<!-- /.modal -->
</form>
</div>
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标签:  bootstrap 表格 按钮
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