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用c语言编写三子棋小游戏

2017-07-30 21:40 441 查看
三子棋小游戏设计为人与电脑进行下棋的操作,相对比较简单的操作,下面为三子棋小游戏的代码。

game.h


#define _CRT_SECURE_NO_WARNINGS 1
#ifndef __GAME_H__
#define __GAME_H__
#include<stdio.h>
#include<stdio.h>
#include<string.h>
#include<time.h>

#define ROWS 3
#define COLS 3
void init_board(char board[ROWS][COLS], int row, int col);
void display_board(char board[ROWS][COLS], int row, int col);
void com_board(char board[ROWS][COLS], int row, int col);
void player_board(char board[ROWS][COLS], int row, int col);

int winner(char board[ROWS][COLS], int row, int col);
int loser(char board[ROWS][COLS], int row, int col);
#endif


game.c


#define _CRT_SECURE_NO_WARNINGS 1
#include"game.h"
void init_board(char board[ROWS][COLS], int row, int col)//棋盘初始化
{
memset(board ,' ', ROWS*COLS*sizeof(board[0][0]));
}
void display_board(char board[ROWS][COLS], int row, int col)//棋盘的打印展示
{
int i = 0;
for (i = 0; i < row; i++)
{
printf(" %c | %c | %c \n", board[i][0], board[i][1], board[i][2]);
if (i != 2)
{
printf("---|---|---\n");//棋盘的设计
}
}
}
void player_board(char board[ROWS][COLS], int row, int col)//玩家下棋
{
int x = 0;
int y = 0;
flag1:
printf("请输入坐标:");
scanf("%d%d",&x,&y);
x = x - 1;
y = y - 1;
if ((x >= 0) && (x <= 2) && (y >= 0) && (y <= 2))
{
if (board[x][y] == ' ')
{
board[x][y] = 'x';
}
else
{
printf("输入错误\n");
goto flag1;
}
}
else
{
goto flag1;
}
printf("\n");
}
void comp_board(char board[ROWS][COLS], int row, int col)//电脑下
{
srand((unsigned int)time(NULL));
while (1)
{
int x = rand() % 3;
int y = rand() % 3;
if (board[x][y] == ' ')
{
board[x][y] = 'o';
break;
}
}
printf("\n");
}
int winner (char board[ROWS][COLS], int row, int col)
{
int i = 0;
int j = 0;
for (i = 0; i < row; i++)
{
if (board[i][0] == board[i][1] && board[i][1] == board[i][2] && board[i][1] == 'x')//人的行判断
{
return 1;
}

if (board[i][0] == board[i][1] && board[i][1] == board[i][2] && board[i][1] == 'o')//电脑的行判断
{
return 2;
}
}
for (j = 0; j < col; j++)
{

if (board[0][j] == board[1][j] && board[1][j] == board[2][j] && board[1][j] == 'x')//人的列判断
{
return 1;
}
if (board[0][j] == board[1][j] && board[1][j] == board[2][j] && board[1][j] == 'o')//电脑的列判断
{
return 2;
}
}
if (board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[1][1] == 'x')//人的斜判断
{
return 1;
}
if (board[0][2] == board[1][1] && board[1][1] == board[2][0] && board[1][1] == 'x')//人的斜判断
{
return 1;
}

if (board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[1][1] == 'o')//电脑的斜判断
{
return 2;
}
if (board[0][2] == board[1][1] && board[1][1] == board[2][0] && board[1][1] == 'o')//电脑的斜判断
{
return 2;
}
int C = is_full(board, ROWS, COLS);//判断是否满了
if (C == 5)
{
return 3;
}
}
int is_full(char board[ROWS][COLS], int row, int col)
{
int i = 0;
int j = 0;
for (i = 0; i < row; i++)
{
for (j = 0; j < col; j++)
{
if (board[i][j] == ' ')
{
return 4;
}
}
}
return 5;
}


test.c


#define _CRT_SECURE_NO_WARNINGS 1
#include"game.h"
void venu()
{
printf("*****************************\n");
printf("******1.play 0.exit**********\n");
printf("*****************************\n");

}
game()
{

char board[ROWS][COLS];
init_board(board, ROWS, COLS);//棋盘初始化
display_board(board, ROWS, COLS);//打印棋盘
while (1)
{
player_board(board, ROWS, COLS);//玩家下棋
display_board(board, ROWS, COLS);
if (winner(board, ROWS, COLS) == 1)
{
printf("你赢了\n");
break;
}
else if (winner(board, ROWS, COLS) == 3)
{
printf("平局\n");
break;
}
comp_board(board, ROWS, COLS);//电脑下棋
display_board(board, ROWS, COLS);
if (winner(board, ROWS, COLS) == 2)
{
printf("电脑赢了\n");
break;

}
else if (winner(board, ROWS, COLS) == 3)
{
printf("平局\n");
break;
}
}
}
int main()
{
int input = 0;
venu();
do
{
printf("请选择 :\n");
scanf("%d", &input);
switch (input)
{
case 1:
game();
break;
case 0:
printf("退出\n");
break;
default:
printf("输入错误");
break;

}
} while (input);
return 0;
}


下面为运行的界面:



本人是初学者,可能设计的过于简易,希望各位给于意见与建议。
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