hpu暑假训练G - New Year and Days【数学】

Today is Wednesday, the third day of the week. What's more interesting is that tomorrow is the last day of the year 2015.

Limak is a little polar bear. He enjoyed this year a lot. Now, he is so eager to the coming year 2016.

Limak wants to prove how responsible a bear he is. He is going to regularly save candies for the entire year 2016! He considers various saving plans. He can save one candy either on some fixed day of the week or on some fixed day of the month.

Limak chose one particular plan. He isn't sure how many candies he will save in the 2016 with his plan. Please, calculate it and tell him.

Input

The only line of the input is in one of the following two formats:

"x of week" wherex (1 ≤ x ≤ 7) denotes the day of the week. The 1-st day is Monday and the 7-th one
is Sunday.
"x of month" wherex (1 ≤ x ≤ 31) denotes the day of the month.

Output

Print one integer — the number of candies Limak will save in the year 2016.

Example

Input

4 of week

Output

52

Input

30 of month

Output

11

Note

Polar bears use the Gregorian calendar. It is the most common calendar and you likely use it too. You can read about it on Wikipedia if you want to –https://en.wikipedia.org/wiki/Gregorian_calendar.
The week starts with Monday.

In the f
4000
irst sample Limak wants to save one candy on each Thursday (the 4-th day of the week). There are52 Thursdays in the 2016. Thus, he will save
52 candies in total.

In the second sample Limak wants to save one candy on the 30-th day of each month. There is the 30-th day in exactly11 months in the 2016 — all months but February. It means that Limak will save11candies in total.

解析：

         首先要知道2016年是闰年，有366天，第一天是周五，最后一天是周六。除了周五周六有53天，其它的只有52天。

        还有就是2月有29天。

        注意输入的格式，如果有更好的方法请联系博主哦。

程序如下：

#include<cstdio>
#include<cstring>
int main()
{
int n;
char c[10];
scanf("%d of ",&n);
gets(c);
int l=strlen(c);
if(l==4)
{
if(n!=5&&n!=6)
printf("52\n");
else
printf("53\n");
}
else
{
if(n>=1&&n<=29)
printf("12\n");
else if(n==30)
printf("11\n");
else
printf("7\n");

}
return 0;
}