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ajax的get 和post方式发送请求

2017-07-19 23:59 477 查看

<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<base href="<%=basePath%>">
<title>My JSP 'index.jsp' starting page</title>
<meta http-equiv="pragma" content="no-cache">
<meta http-equiv="cache-control" content="no-cache">
<meta http-equiv="expires" content="0">
<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
<meta http-equiv="description" content="This is my page">
<script type="text/javascript" src="js/jquery-1.12.4.min.js"></script>

<script type="text/javascript">
function valDateEmian(hag){
//createGetHttpRequst(hag.value);
createPostHttpRequst(hag.value);

}
var xmlHttpRequest;

function createGetHttpRequst(name){

xmlHttpRequest=new XMLHttpRequest();
//2调用回调函数
xmlHttpRequest.onreadystatechange=callBack;
//3初始化xmlhttpreqost组件
xmlHttpRequest.open("GET","UserServlet?name="+name,true);
//4发送请求
xmlHttpRequest.send(null);
}
function createPostHttpRequst(name){
xmlHttpRequest=new XMLHttpRequest();
xmlHttpRequest.onreadystatechange=callBack;
xmlHttpRequest.open("POST","UserServlet",true);
xmlHttpRequest.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");
xmlHttpRequest.send("name="+name+"&opr=index");
}

//设置回调函数
function callBack(){
if (xmlHttpRequest.readyState==4 && xmlHttpRequest.status==200) {
var date =xmlHttpRequest.responseText;
document.getElementById("emain").innerHTML=date;

}

}
</script>
</head>

<body>
邮箱    ：<input type="text" onblur="valDateEmian(this)" /><span id="emain"> </span>
用户名    ：<input type="text" />    <span id="emain"> </span>
密码    ：<input type="text" />    <span id="emain"> </span>
</body>
</html>

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