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Python 案例 004 (计算当前时间是一年中的第几天)

2017-07-17 22:03 585 查看
# -*- coding:utf-8 -*-

"""
计算当前时间是一年中的第几天
"""

bissextile = [31,60,91,121,152,182,213,244,274,305,335,366] #leap year
commonYear =[31,59,90,120,151,181,212,243,273,304,334,365]
enterYear = int(raw_input("enter the Year :"))
enterMonth = int(raw_input("enter the Month :"))
enterDay = int(raw_input("enter the Day :"))
remained = 0
# first need to check is leap or common year
if (enterYear%100 !=0) and (enterYear %4 == 0 ) or (enterYear%400 == 0):
if enterMonth > 1 :
remained = bissextile[enterMonth-1] + enterDay
else:
remained = enterDay
else:
if enterMonth > 1 :
remained = commonYear[enterMonth-1] + enterDay
else:
remained = enterDay
print remained

"""
enter the Year :2014
enter the Month :1
enter the Day :15
15

enter the Year :2018
enter the Month :6
enter the Day :12
193

"""

'''
还需要更严格的限制条件,才成。
'''
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