jQuery ajax()使用serialize()提交数据

<form id = "myForm">
<input type = "text" id = "name" name = "name" value = "张三"/>
<input type = "checkbox" name = "hobby" value = "吃饭"/>吃饭 <br/>
<input type = "checkbox" name = "hobby" value = "睡觉"/>睡觉 <br/>
<input type = "checkbox" name = "hobby" value = "打豆豆"/>打豆豆 <br/>
..........
<input type = "hidden" id = "saveUrl" name = "saveUrl" value = "myAction.do">
</form>

//提交Form表单所有的值
$.ajax({
url: $("#saveUrl").val() + "?" +$('input[name="hobby"]:checked').serialize(),
type:"post",
dataType:"json",
data:$('#myForm').serialize(),
success: function(data){
alert(13, data.message);
},
error: function(){
alert(21, "提交失败");
}
});

//单独提交选中的checkBox 和某些需要提交的数据
$.ajax({
//$('input[name="hobby"]:checked').serialize()的数据形式为  "hobby=吃饭&hobby=睡觉&hobby=打豆豆" ，所以我们可以直接拼在路径请求后面
url: $("#saveUrl").val() + "?" +$('input[name="hobby"]:checked').serialize(),
type: "post",
dataType: "json",
//          data: $('#myForm').serialize(),
data: {
name : $('#name').val() ,
.......
},
success: function(data){
alert(13, data.message);
},
error: function(){
alert(21, "提交失败");
}
});

获取多个checkbox值
String[] hobbies = request.getParameterValues("hobby");
获取其他....
String name = request.getParameter("name");
.....