leetcode[Range Sum Query - Immutable]//待整理多种解法
2017-07-10 10:48
417 查看
public class NumArray { int[] nums = null; public NumArray(int[] nums) { this.nums = nums; } public int sumRange(int i, int j) { if(i < 0 || j >= nums.length){ return 0; } else{ int sum = 0; for(int k = i; k <= j; k++){ sum += nums[k]; } return sum; } } } /** * Your NumArray object will be instantiated and called as such: * NumArray obj = new NumArray(nums); * int param_1 = obj.sumRange(i,j); */
相关文章推荐
- Leetcode第303 Range Sum Query - Immutable(简单动态规划解法)
- Leetcode: Range Sum Query - Immutable
- LeetCode 304. Range Sum Query 2D – Immutable
- LeetCode-303. Range Sum Query - Immutable
- [leetcode] 304. Range Sum Query 2D - Immutable 解题报告
- leetcode - 303. Range Sum Query - Immutable 【动态规划 + 间接逼近目标 + 区间计算 +刻度 + 距离计算方式 】
- 【LEETCODE】303-Range Sum Query - Immutable
- [Leetcode]303. Range Sum Query - Immutable
- leetcode_Range Sum Query - Immutable
- Java [Leetcode 303]Range Sum Query - Immutable
- LeetCode *** 304. Range Sum Query 2D - Immutable
- LeetCode(304)Range Sum Query 2D - Immutable
- leetcode 304. Range Sum Query 2D - Immutable
- LeetCode-Easy部分中标签为Dynamic Programming 303 Range Sum Query - Immutable
- [LeetCode]303. Range Sum Query - Immutable
- [LeetCode]Range Sum Query 2D - Immutable
- LeetCode No.303 Range Sum Query - Immutable
- leetcode解题之303# Range Sum Query - Immutable Java版 (多次计算数组内任意两个下标之间的和)
- leetcode(58)-Range Sum Query - Immutable
- [leetcode-303]Range Sum Query - Immutable