Kruskal算法求解最小生成树的Java实现
2017-07-06 20:39
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假设一个无向图共有V(V>1)个顶点,E条边,那么它的最小生成树(如果有的话)有V个顶点,V-1条边。Krusal算法在求解最小生成树的过程中就是不断地选出一条权重最小的边,如果将这条边插入到目前的最小生成树(此时尚未最终形成)中不形成环路,则将其插入,否则再选择次小边重复以上过程,直到最后最小生成树中有V-1条边,则最小生成树求解成功,否则,原图中不包含最小生成树。
下面是《算法导论》一书中的一个Krusal算法求解最小生成树过程的一个例子。
以下是具体的Java代码实现
package Kruskal;
/**
* 边
* @author sdu20
*
*/
public class Edge {
private int v1;
private int v2;
private int weight;
/**
* 为查找最小边专门所设
* @param weight
*/
public Edge(int weight){
this.v1 = -1;
this.v2 = -1;
this.weight = weight;
}
public Edge(int v1,int v2,int weight){
this.v1 = v1;
this.v2 = v2;
this.weight = weight;
}
public int getV1(){
return v1;
}
public int getV2(){
return v2;
}
public int getWeight(){
return weight;
}
public String toString(){
String str = "[ "+v1+" , "+v2+" , "+weight+" ]";
return str;
}
public boolean equals(Edge edge){
boolean equal = this.v1==edge.getV1() && this.v2==edge.getV2() && this.weight==edge.getWeight()
|| this.v1==edge.getV2() && this.v2==edge.getV1() && this.weight==edge.getWeight();
return equal;
}
}
运行截图如下
该测试用例即为前面所给的例子。
下面是《算法导论》一书中的一个Krusal算法求解最小生成树过程的一个例子。
以下是具体的Java代码实现
package Kruskal;
/**
* 边
* @author sdu20
*
*/
public class Edge {
private int v1;
private int v2;
private int weight;
/**
* 为查找最小边专门所设
* @param weight
*/
public Edge(int weight){
this.v1 = -1;
this.v2 = -1;
this.weight = weight;
}
public Edge(int v1,int v2,int weight){
this.v1 = v1;
this.v2 = v2;
this.weight = weight;
}
public int getV1(){
return v1;
}
public int getV2(){
return v2;
}
public int getWeight(){
return weight;
}
public String toString(){
String str = "[ "+v1+" , "+v2+" , "+weight+" ]";
return str;
}
public boolean equals(Edge edge){
boolean equal = this.v1==edge.getV1() && this.v2==edge.getV2() && this.weight==edge.getWeight()
|| this.v1==edge.getV2() && this.v2==edge.getV1() && this.weight==edge.getWeight();
return equal;
}
}
package Kruskal; import java.util.*; public class Graph { private int vNum; private int edgeNum; private LinkedList<Edge>[] edgeLinks; private LinkedList<Edge> T; //入选的边集 private LinkedList<Integer>[] kindLists; //用于区分是否形成环 public Graph(int vNum){ this.vNum = vNum; this.edgeNum = 0; edgeLinks = new LinkedList[vNum]; for(int i = 0;i<vNum;i++){ edgeLinks[i] = new LinkedList<>(); } } public void insertEdge(Edge edge){ int v1 = edge.getV1(); int v2 = edge.getV2(); edgeLinks[v1].add(edge); Edge edge2 = new Edge(v2,v1,edge.getWeight()); edgeLinks[v2].add(edge2); edgeNum++; } public void deleteEdge(Edge edge){ int v1 = edge.getV1(); int v2 = edge.getV2(); edgeLinks[v1].remove(edge); for(int i = 0;i<edgeLinks[v2].size();i++){ Edge edge2 = edgeLinks[v2].get(i); if(edge2.equals(edge)){ edgeLinks[v2].remove(edge2); break; } } edgeNum--; } public void bianli(){ System.out.println("共有 "+vNum+" 个顶点, "+edgeNum+" 条边。"); for(int i = 0;i<vNum;i++){ LinkedList<Edge> list = (LinkedList<Edge>) edgeLinks[i].clone(); System.out.print(i+" : ["); while(!list.isEmpty()){ Edge edge = list.pop(); System.out.print(edge.getV2()+"("+edge.getWeight()+")"+" "); } System.out.println("]"); } } /** * Kruskal算法实现 */ public void Kruskal(){ T = new LinkedList<>(); kindLists = new LinkedList[vNum]; for(int i = 0;i<vNum;i++){ kindLists[i] = new LinkedList<>(); int num = i; kindLists[i].add(num); } while(edgeNum>0 && T.size()!=vNum-1){ Edge edge = this.getMinEdge(); this.deleteEdge(edge); int v1 = edge.getV1(); int v2 = edge.getV2(); int containsV1 = -1; int containsV2 = -1; for(int i = 0;i<vNum;i++){ LinkedList<Integer> list = (LinkedList<Integer>) kindLists[i].clone(); if(list.contains(v1)){ containsV1 = i; } if(list.contains(v2)){ containsV2 = i; } } if(containsV1 != containsV2){ T.add(edge); while(!kindLists[containsV2].isEmpty()){ kindLists[containsV1].add(kindLists[containsV2].pop()); } } } if(T.size() == vNum-1){ System.out.println("求最小生成树成功"); int sumWeight = 0; LinkedList<Edge> TT = (LinkedList<Edge>) T.clone(); while(!TT.isEmpty()){ Edge ee = TT.pop(); sumWeight += ee.getWeight(); System.out.println(ee.toString()); } System.out.println("最小生成树权重之和为: "+sumWeight); }else{ System.out.println("没有最小生成树"); } } public Edge getMinEdge(){ Edge minEdge = new Edge(10000); for(int i = 0;i<vNum;i++){ LinkedList<Edge> list = (LinkedList<Edge>) edgeLinks[i].clone(); while(!list.isEmpty()){ Edge edge = list.pop(); if(minEdge.getWeight()>edge.getWeight()){ minEdge = edge; } } } if(minEdge.getWeight()==10000) return null; return minEdge; } }
package Kruskal; public class Main { public static void main(String[] args) { // TODO Auto-generated method stub bookGraph(); //randomGraph(); } public static void bookGraph(){ Graph graph = new Graph(9); Edge[] edges = new Edge[14]; edges[0] = new Edge(0,1,4); edges[1] = new Edge(0,7,8); edges[2] = new Edge(1,2,8); edges[3] = new Edge(1,7,11); edges[4] = new Edge(2,3,7); edges[5] = new Edge(2,5,4); edges[6] = new Edge(2,8,2); edges[7] = new Edge(3,4,9); edges[8] = new Edge(3,5,14); edges[9] = new Edge(4,5,10); edges[10] = new Edge(5,6,2); edges[11] = new Edge(6,7,1); edges[12] = new Edge(6,8,6); edges[13] = new Edge(7,8,7); for(int i = 0;i<14;i++){ graph.insertEdge(edges[i]); } graph.bianli(); graph.Kruskal(); } /** * 100个点,1000条边,权重为1~100的随机数 */ public static void randomGraph(){ Graph graph = new Graph(100); for(int i = 0;i<1000;){ int preV = (int)(Math.random()*100); int folV = (int)(Math.random()*100); int weight = (int)(Math.random()*100+1); if(preV != folV){ Edge edge = new Edge(preV,folV,weight); try{ graph.insertEdge(edge); i++; }catch(Exception e){ continue; } } } graph.bianli(); graph.Kruskal(); } }
运行截图如下
该测试用例即为前面所给的例子。
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