MySQL的多表联合查询

一.多表查询简介:

连接查询:

交叉连接:

交叉连接:查询到的是两个表的笛卡尔积

语法:

select * from 表1 cross join 表2 on关联条件

内连接:(inner join , 其中inner可以省略)

显示内连接:在SQL中显示的调用inner join关键字

语法:

select * from 表1 inner join 表2 on 关联条件

隐式内连接:在SQL中没有调用inner join关键字

语法:

select * from 表1,表2 where 关联条件

外链接:(outer join , outer是可以省略的)

左外连接:

语法:select * from 表1 left outer join 表2 on 关联条件

右外连接:

语法:select * from 表1 right outer join 表2 on 关联条件

子查询:

子查询:一个查询语句条件需要依赖另一个语句的结果

主要关键字有:in,any,all和exis四个.其中比较常用的是in;

实例如下:

1.

这里写代码片

– 1、查询平均成绩大于70分的同学的学号和平均成绩

SELECT s.id,AVG(sc.score) FROM student s,studentcourse sc WHERE s.id=sc.student_id GROUP BY s.id HAVING AVG(sc.score)>70;



– 2、查询所有同学的学号、姓名、选课数、总成绩

SELECT s.id,s.name,COUNT(c.id),SUM(sc.score) FROM student s,course c,studentcourse sc WHERE s.id=sc.student_id AND c.id=sc.course_id GROUP BY s.id;



– 3、查询没学过关羽老师课的同学的学号、姓名

– 分解:3.1所有选择该老师的学生

SELECT s.name,s.id FROM student s,course c,studentcourse sc,teacher t WHERE t.id=c.teacher_id AND s.id=sc.student_id AND c.id=sc.course_id AND t.id =1 GROUP BY s.id;

– 分解:3.2 去除3.1中的所有学生

SELECT s.name,s.id FROM student s WHERE s.id NOT IN (SELECT s.id FROM student s,course c,studentcourse sc,teacher t WHERE t.id=c.teacher_id AND s.id=sc.student_id AND c.id=sc.course_id AND t.name =’关羽’);

– 第二种方法:

SELECT id,NAME

FROM student

WHERE id NOT IN (SELECT student_id

FROM studentcourse

WHERE course_id IN (SELECT course.id

FROM teacher,course

WHERE teacher.id=course.teacher_id

AND teacher.name=’关羽’));



– 4、查询学过赵云老师所教课的同学的学号、姓名

SELECT s.name,s.id

FROM student s

WHERE s.id IN(SELECT student_id

FROM studentcourse

WHERE course_id IN(SELECT course.id

FROM teacher,course

WHERE teacher.id=course.teacher_id

AND teacher.name=’赵云’));



– 5、查询没有学三门课以上的同学的学号、姓名

SELECT id,NAME

FROM student

WHERE student.id NOT IN (SELECT s.id

FROM studentcourse sc,student s

WHERE sc.student_id=s.id GROUP BY s.id HAVING COUNT(sc.course_id)>=3);



– 6、查询各科成绩最高和最低的分：以如下形式显示：课程ID，最高分，最低分；

SELECT c.id AS ‘课程ID’,

MAX(sc.score) AS ‘最高分’,

MIN(sc.score)AS ‘最低分’

FROM studentcourse sc,course c

WHERE sc.course_id=c.id

GROUP BY c.id;



– 7、查询学生信息和平均成绩

SELECT s.id,s.name,s.city,s.age, c.name,sc.score,t.name

FROM student s,studentcourse sc,course c,teacher t

WHERE s.id=sc.student_id AND c.id=sc.course_id AND c.teacher_id=t.id GROUP BY s.id;



– 8、查询上海和北京学生数量

SELECT s.city,COUNT(*)

FROM student s

WHERE s.city IN(‘上海’,’北京’)GROUP BY s.city;



– 9、查询不及格的学生信息和课程信息

SELECT s.id,s.name,c.name,sc.score

FROM student s,studentcourse sc,course c

WHERE s.id=sc.student_id AND c.id=sc.course_id GROUP BY s.id HAVING sc.score<60;



– 10、统计每门课程学生选修人数（超过四人的进行统计)

SELECT c.id,c.name,COUNT(sc.course_id)

FROM course c,studentcourse sc

WHERE c.id=sc.course_id GROUP BY c.id HAVING COUNT(sc.course_id)>4;



– 11按平均成绩从低到高显示所有学生课程成绩，按如下形式显示： 学生ID,课程名,学生选课数,平均分；

SELECT s.name AS ‘学生’,

(SELECT sc.score FROM studentcourse sc WHERE sc.student_id=s.id AND sc.course_id=1) AS ‘骑马’ ,

(SELECT sc.score FROM studentcourse sc WHERE sc.student_id=s.id AND sc.course_id=2) AS ‘射箭’ ,

(SELECT sc.score FROM studentcourse sc WHERE sc.student_id=s.id AND sc.course_id=3) AS ‘忍术’ ,

(SELECT sc.score FROM studentcourse sc WHERE sc.student_id=s.id AND sc.course_id=4) AS ‘战术’ ,

(SELECT sc.score FROM studentcourse sc WHERE sc.student_id=s.id AND sc.course_id=5) AS ‘格斗’ ,

COUNT(sc.course_id) AS ‘选课数’,

AVG(sc.score) ‘平均分’

FROM student s,studentcourse sc,course c

WHERE s.id=sc.student_id AND c.id=sc.course_id

GROUP BY s.id

ORDER BY AVG(sc.score) DESC;



– 12.按各科平均成绩从低到高和及格率的百分数从高到低顺序；

SELECT c.id,c.name,AVG(sc.score),

SUM(CASE WHEN IFNULL(sc.Score,0)>=60 THEN 1 ELSE
9e08
0 END)/COUNT(*) AS ‘Percent(%)’

FROM studentcourse sc,course c

WHERE sc.course_id=c.id

GROUP BY c.id



– 13.查询不同老师所教不同课程平均分从高到低显示；

SELECT c.id,c.name,t.name,AVG(sc.score)

FROM studentcourse sc,course c,teacher t

WHERE c.id=sc.course_id AND c.teacher_id=t.id

GROUP BY c.id

ORDER BY AVG(sc.score) DESC;



– 14 检索射箭课程分数，按分数降序排列,显示:同学学号,姓名

SELECT s.id,s.name,AVG(sc.score)

FROM student s,studentcourse sc,course c

WHERE s.id=sc.student_id AND c.id=sc.course_id AND c.name=’射箭’

GROUP BY s.id

ORDER BY AVG(sc.score) DESC;



– 15.查询两门以上不及格课程的同学的学号及其平均成绩,显示:学生id,学生name,平均分

SELECT s.id,s.name,AVG(sc.score)

FROM student s,studentcourse sc,course c

WHERE s.id=sc.student_id AND sc.score<60 AND s.id IN

(

SELECT sc.student_id FROM studentcourse sc,course c

WHERE sc.course_id=c.id AND sc.score<60

GROUP BY sc.student_id HAVING COUNT(*)>2

)

GROUP BY s.id;

好多都是一样的,需要总结规律,以上,感觉学完之后好长时间不用就会忘得好快,写在这里,可以自己偶尔看看!