用python将%格式化字符串转换成xliff格式

1. xliff是什么

2. 代码

class XliffMaker(object):
"""class for XliffMaker"""
def __init__(self, s):
super(XliffMaker, self).__init__()
self.s = s

def make(self):
reg = re.compile(STRING_REGEX)
idx = 1
targetStrHead = '<xliff:g id="FMT_STR_ID">'
targetStrBoot = '</xliff:g>'
targetStr = targetStrHead
mediemStr = ""

otherStrList = reg.split(self.s)

replacedList = []
for m in reg.finditer(self.s):
s0 = m.group()
s1 = ""
if 'd' in s0:
reg0 = re.compile(r'%(\d+)d')
s1 = '%%%d$%sd' % (idx, reg0.search('%2d').group(1))
elif 's' in s0:
s1 = '%%%d$s' % idx
replacedList.append(s1)
idx = idx + 1

ret = zip(otherStrList, replacedList)
for t in ret:
mediemStr = mediemStr + "".join(t)
mediemStr = mediemStr + otherStrList[-1]

return targetStr + mediemStr + targetStrBoot