How do you specify a byte literal in Java?
2017-05-24 09:51
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问题： If I have a method
void f(byte b);
how can I call it with a numeric argument without casting?
f(0);gives an error.
答案：[/code]
You cannot. A basic numeric constant is considered an integer (or long if followed by a "L"), so you must explicitly downcast it to a byte to pass it as a parameter. As far as I know there is no shortcut.
f((byte)0);
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