ZigZag Conversion
2017-05-16 17:01
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leetcode中的曲折转换问题
The string
this: (you may want to display this pattern in a fixed font for better legibility)
And then read line by line:
Write the code that will take a string and make this conversion given a number of rows:
return
代码如下:
public class ZigZagConversion {
public String convert(String s, int nRows){
char[] c = s.toCharArray();
int len = c.length;
StringBuffer[] sb = new StringBuffer[nRows];
for(int i = 0; i < sb.length; i++)
sb[i] = new StringBuffer();
int i = 0;
while(i < len){
//垂直向下
for(int idx = 0; idx < nRows && i < len; idx++){
sb[idx].append(c[i++]);
}
//斜向上
for(int idx = nRows - 2; idx >= 1 && i < len; idx--){
sb[idx].append(c[i++]);
}
}
//组合成一个string
for(int idx = 1;idx < sb.length; idx++){
sb[0].append(sb[idx]);
}
return sb[0].toString();
}
}
The string
"PAYPALISHIRING"is written in a zigzag pattern on a given number of rows like
this: (you may want to display this pattern in a fixed font for better legibility)
P A H N A P L S I I G Y I R
And then read line by line:
"PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
string convert(string text, int nRows);
convert("PAYPALISHIRING", 3)should
return
"PAHNAPLSIIGYIR".
代码如下:
public class ZigZagConversion {
public String convert(String s, int nRows){
char[] c = s.toCharArray();
int len = c.length;
StringBuffer[] sb = new StringBuffer[nRows];
for(int i = 0; i < sb.length; i++)
sb[i] = new StringBuffer();
int i = 0;
while(i < len){
//垂直向下
for(int idx = 0; idx < nRows && i < len; idx++){
sb[idx].append(c[i++]);
}
//斜向上
for(int idx = nRows - 2; idx >= 1 && i < len; idx--){
sb[idx].append(c[i++]);
}
}
//组合成一个string
for(int idx = 1;idx < sb.length; idx++){
sb[0].append(sb[idx]);
}
return sb[0].toString();
}
}
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