您的位置:首页 > 编程语言 > Python开发

Python制作Windows系统服务

2017-03-25 15:04 701 查看

最近有个Python程序需要安装并作为Windows系统服务来运行,过程中碰到一些坑,整理了一下。

Python服务类

首先Python程序需要调用一些Windows系统API才能作为系统服务,具体内容如下:

#!/usr/bin/env python
# -*- coding: utf-8 -*-
import sys
import time
import win32api
import win32event
import win32service
import win32serviceutil
import servicemanager
class MyService(win32serviceutil.ServiceFramework):
_svc_name_ = "MyService"
_svc_display_name_ = "My Service"
_svc_description_ = "My Service"
def __init__(self, args):
self.log('init')
win32serviceutil.ServiceFramework.__init__(self, args)
self.stop_event = win32event.CreateEvent(None, 0, 0, None)
def SvcDoRun(self):
self.ReportServiceStatus(win32service.SERVICE_START_PENDING)
try:
self.ReportServiceStatus(win32service.SERVICE_RUNNING)
self.log('start')
self.start()
self.log('wait')
win32event.WaitForSingleObject(self.stop_event, win32event.INFINITE)
self.log('done')
except BaseException as e:
self.log('Exception : %s' % e)
self.SvcStop()
def SvcStop(self):
self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
self.log('stopping')
self.stop()
self.log('stopped')
win32event.SetEvent(self.stop_event)
self.ReportServiceStatus(win32service.SERVICE_STOPPED)
def start(self):
time.sleep(10000)
def stop(self):
pass
def log(self, msg):
servicemanager.LogInfoMsg(str(msg))
def sleep(self, minute):
win32api.Sleep((minute*1000), True)
if __name__ == "__main__":
if len(sys.argv) == 1:
servicemanager.Initialize()
servicemanager.PrepareToHostSingle(MyService)
servicemanager.StartServiceCtrlDispatcher()
else:
win32serviceutil.HandleCommandLine(MyService)

pyinstaller打包

pyinstaller -F MyService.py

测试

# 安装服务
dist\MyService.exe install
# 启动服务
sc start MyService
# 停止服务
sc stop MyService
# 删除服务
sc delete MyService

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持脚本之家。

您可能感兴趣的文章:

内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签:  Python Windows