简单的一个用定时器控制的流水灯c程序

用定时器以间隔500MS在6位数码管上依次显示0、1、2、3….C、D、E、F，重复。

#include<reg52.h>

typedef unsigned int u8;

typedef unsigned char u16;

u8 code table[]={

0x3f,0x06,0x5b,0x4f,

0x66,0x6d,0x7d,0x07,

0x7f,0x6f,0x77,0x7c,

0x39,0x5e,0x79,0x71};

u8 code weixuan[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf};

sbit duan=P2^6;

sbit wei=P2^7;

u8 i=0,j=0;

void time0()

{

    TH0=(65536-5000)/256;

 TL0=(65536-5000)%256;

 EA=1;

 ET0=1;

 TR0=1;

 while(1);

}

void main() 

{

  TMOD=0x01;

  time0();

}

void time1() interrupt 1

{ 

 wei=0;

 P0=weixuan[(i++)%16];

   wei=1;

  duan=0;

   P0=table[(j++)%6];

   duan=1;

   TH0=(65536-5000)/256;

 TL0=(65536-5000)%256;

}