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Android应用获取通知栏权限是否开启--以及跳转到系统设置界面--解决方案

2017-03-03 20:49 781 查看
因为项目用到推送功能,所以需求是知道用户是否开启了通知栏的权限,并且提供滑动按钮进行跳转以便用户进行关闭或者开启。1.获取通知栏权限是否开启:
/*** 获取通知栏权限是否开启**/public class NotificationsUtils {private static final String CHECK_OP_NO_THROW = "checkOpNoThrow";private static final String OP_POST_NOTIFICATION = "OP_POST_NOTIFICATION";@SuppressLint("NewApi")public static boolean isNotificationEnabled(Context context) {AppOpsManager mAppOps = (AppOpsManager) context.getSystemService(Context.APP_OPS_SERVICE);ApplicationInfo appInfo = context.getApplicationInfo();String pkg = context.getApplicationContext().getPackageName();int uid = appInfo.uid;Class appOpsClass = null;/* Context.APP_OPS_MANAGER */try {appOpsClass = Class.forName(AppOpsManager.class.getName());Method checkOpNoThrowMethod = appOpsClass.getMethod(CHECK_OP_NO_THROW, Integer.TYPE, Integer.TYPE,String.class);Field opPostNotificationValue = appOpsClass.getDeclaredField(OP_POST_NOTIFICATION);int value = (Integer) opPostNotificationValue.get(Integer.class);return ((Integer) checkOpNoThrowMethod.invoke(mAppOps, value, uid, pkg) == AppOpsManager.MODE_ALLOWED);} catch (ClassNotFoundException e) {e.printStackTrace();} catch (NoSuchMethodException e) {e.printStackTrace();} catch (NoSuchFieldException e) {e.printStackTrace();} catch (InvocationTargetException e) {e.printStackTrace();} catch (IllegalAccessException e) {e.printStackTrace();}return false;}}
2.进入系统设置界面
protected void requestPermission(int requestCode) {// TODO Auto-generated method stub// 6.0以上系统才可以判断权限if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.BASE) {// 进入设置系统应用权限界面Intent intent = new Intent(Settings.ACTION_SETTINGS);startActivity(intent);return;} else if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.LOLLIPOP) {// 运行系统在5.x环境使用// 进入设置系统应用权限界面Intent intent = new Intent(Settings.ACTION_SETTINGS);startActivity(intent);return;}return;}
这个功能不是特别重要,但是有时候确实有这样的需求。原文地址:http://blog.csdn.net/qq_22637473/article/details/53466425
                                            
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