[LeetCode]1. Two Sum

Given an array of integers, return indices of the two numbers such that they add up to a specific target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

My solution

class Solution {
public:
vector<int> result;
for (int i = 0; i < nums.size(); i++) {
for (int j = i + 1; j < nums.size(); j++) {
if (nums[i] + nums[j] == target) {
result.push_back(i);
result.push_back(j);
return result;
}
}
}
}

Another possible solution

*Use hashtable for efficiency