您的位置:首页 > 运维架构 > Linux

Linux-在文本最后一行最后一列处理数据

2016-12-26 16:07 1586 查看
1,假设有文本数据txt内容如下:

          1 2 3

          4 5 6

          7 8 9

     问题1: 现要在 最后一行最后一个数字 9 后面添加一个字符 ’]' ,得到如下内容

                  1 2 3

                  4 5 6

                  7 8 9]

      命令一:awk 'NR>1{print a}{a=$0}END{print gensub(/$/,"]",$0)}' txt

      命令二:awk 'BEGIN{getline a}{print a;a=$0}END{$0=gensub(/$/,"]",1,$0);print} ' txt

      [b]命令三:awk
'{if(!getline line){print gensub(/$/,"]",1,$0)}else{print line?$0 RS line:$0}}' txt
[/b]



     问题2:现要在最后一行最后一个数字 9 后面添加一个字符 ’ ]' ,得到如下内容

                  1 2 3

                  4 5 6

                  7 8 9 ]
      命令一:awk 'NR>1{print a}{a=$0}END{print gensub(/$/," ]",$0)}' txt     

      命令二:awk 'BEGIN{getline a}{print a;a=$0}END{$0=gensub(/$/," ]",1,$0);print} ' txt

      [b]命令三:awk
'{if(!getline line){print gensub(/$/," ]",1,$0)}else{print line?$0 RS line:$0}}' txt

[/b]

       (和问题1的命令相比,"
]"多加了个空格)


     问题3:现要将最后一行最后一个数字 9 替换成字符 ’]' ,得到如下内容

                  1 2 3

                  4 5 6

                  7 8 ]
       命令一:awk
'NR>1{print a}{a=$0}END{print gensub(/.$/,"]",$0)}' txt  


      
命令二:awk 'BEGIN{getline a}{print a;a=$0}END{$0=gensub(/.$/,"]",1,$0);print}' txt


      
命令三:awk '{if(!getline line){print gensub(/.$/,"]",1,$0)}else{print line?$0 RS line:$0}}' txt


       (和问题1的命令相比,/.$/
多了个点)




      问题4:现要将最后一行最后一个数字
9 替换成字符 ’]' ,得到如下内容

                  1 2 3

                  4 5 6

                  7 8]
      命令一:awk
'NR>1{print a}{a=$0}END{print gensub(/..$/,"]",$0)}' txt


     
命令二:awk 'BEGIN{getline a}{print a;a=$0}END{$0=gensub(/..$/,"]",1,$0);print}' txt


      [b]命令三:awk
'{if(!getline line){print gensub(/..$/,"]",1,$0)}else{print line?$0 RS line:$0}}' txt

[/b]

       [b](和问题3的命令相比,/..$/
又多了个点,可以看出多加一个点,就向前多移1位)

[/b]

   
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: