您的位置:首页 > 其它

Implement atoi to convert a string to an integer.

2016-12-17 11:45 399 查看
package com.dengpf.StringToInteger;

/**
* Created by kobe73er on 16/12/17.
*/
public class Solution {
public int myAtoi(String str) {
if (str == null || str.length() < 1)
return 0;

// trim white spaces
str = str.trim();

char flag = '+';

// check negative or positive
int i = 0;
if (str.charAt(0) == '-') {
flag = '-';
i++;
} else if (str.charAt(0) == '+') {
i++;
}
// use double to store result
double result = 0;

// calculate value
while (str.length() > i && str.charAt(i) >= '0' && str.charAt(i) <= '9') {
result = result * 10 + (str.charAt(i) - '0');
i++;
}

if (flag == '-')
result = -result;

// handle max and min
if (result > Integer.MAX_VALUE)
return Integer.MAX_VALUE;

if (result < Integer.MIN_VALUE)
return Integer.MIN_VALUE;

return (int) result;

}

public static void main(String args[]) {
Solution solution = new Solution();
System.out.println(solution.myAtoi(""));
}

}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: