Leetcode 455 Assign Cookies
2016-11-29 13:32
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Assume you are an awesome parent and want to give your children some cookies. But, you should give each child at most one cookie. Each child i has a greed factor gi,
which is the minimum size of a cookie that the child will be content with; and each cookie j has a size sj. If sj >=
gi, we can assign the cookie j to the child i, and the child i will be content. Your goal is to maximize the number of your content children and
output the maximum number.
Note:
You may assume the greed factor is always positive.
You cannot assign more than one cookie to one child.
Example 1:
Example 2:
这是一个典型的双指针的问题。值得注意的是,要先对两个数组进行排序。
我没想到这一点==
public class Solution {
public int findContentChildren(int[] g, int[] s) {
Arrays.sort(g);//注意Array.sort的用法
Arrays.sort(s);
int i=0;
int j=0;
while(i<g.length && j<s.length ){
if(g[i]<=s[j]) i++;//注意这个地方,找到符合条件的进行后移 不然一直后移j直到符合条件或者结束遍历
j++;
}
return i;
}
}
which is the minimum size of a cookie that the child will be content with; and each cookie j has a size sj. If sj >=
gi, we can assign the cookie j to the child i, and the child i will be content. Your goal is to maximize the number of your content children and
output the maximum number.
Note:
You may assume the greed factor is always positive.
You cannot assign more than one cookie to one child.
Example 1:
Input: [1,2,3], [1,1] Output: 1 Explanation: You have 3 children and 2 cookies. The greed factors of 3 children are 1, 2, 3. And even though you have 2 cookies, since their size is both 1, you could only make the child whose greed factor is 1 content. You need to output 1.
Example 2:
Input: [1,2], [1,2,3] Output: 2 Explanation: You have 2 children and 3 cookies. The greed factors of 2 children are 1, 2. You have 3 cookies and their sizes are big enough to gratify all of the children, You need to output 2.
这是一个典型的双指针的问题。值得注意的是,要先对两个数组进行排序。
我没想到这一点==
public class Solution {
public int findContentChildren(int[] g, int[] s) {
Arrays.sort(g);//注意Array.sort的用法
Arrays.sort(s);
int i=0;
int j=0;
while(i<g.length && j<s.length ){
if(g[i]<=s[j]) i++;//注意这个地方,找到符合条件的进行后移 不然一直后移j直到符合条件或者结束遍历
j++;
}
return i;
}
}
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