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10进制与62进制互相转换

2016-10-26 20:54 417 查看
遇到将数字(Decimal)以62进制编码的问题,这里所谓62进制是指采用0~9A~Za~z等62个字符进行编码(按ASCII顺序由小到大)。

Note:这里以`6位编码`为例实现(C#,其他语言类似,或许有更有效的方式),实际中可根据需要调整,不过注意其表述的数值大小范围(eg:6位编码最大值:56800235583(long))。


10进制——>62进制

/// <summary>
/// 将数字转为62进制
/// </summary>
/// <param name="num">待转换的数字</param>
/// <returns>编码字符串</returns>
public static string EncodeStr(long num)
{
int scale = 62;
StringBuilder sb = new StringBuilder();
char[] charArray = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz".ToCharArray();

long remainder = 0;

do
{
remainder = num % scale;
sb.Append(charArray[remainder]);
num = num / scale;
}
while (num > scale - 1);

sb.Append(charArray[num]);

char[] chars = sb.ToString().ToCharArray();
Array.Reverse(chars);
string result = new string(chars);

// 6 bits are required, add leading zeros when the encoded string < 6 long
return result.PadLeft(6, '0');
}


62进制——>10进制

/// <summary>
/// 62进制字符串转为数字
/// </summary>
/// <param name="str">编码字符串</param>
/// <returns>解码后的数字</returns>
public static long DecodeNum(string str)
{
int scale = 62;
string charArray = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz";

// Trim the leading zeros first
str = Regex.Replace(str, "^0*", "");

long num = 0;
int index = 0;
for(int i = 0; i < str.Length; i++)
{
index = charArray.IndexOf(str[i]);
num += (long)(index * (Math.Pow(scale, str.Length - i - 1)));
}

return num;
}


If you have any questions or any bugs are found, please feel free to contact me.

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