POJ 1006 Biorhythms【中国剩余定理】

Description

Some people believe that there are three cycles in a person's life that start the day he or she is born. These three cycles are the physical, emotional, and intellectual cycles, and they have periods of lengths
23, 28, and 33 days, respectively. There is one peak in each period of a cycle. At the peak of a cycle, a person performs at his or her best in the corresponding field (physical, emotional or mental). For example, if it is the mental curve, thought processes
will be sharper and concentration will be easier. 

Since the three cycles have different periods, the peaks of the three cycles generally occur at different times. We would like to determine when a triple peak occurs (the peaks of all three cycles occur in the same day) for any person. For each cycle, you will
be given the number of days from the beginning of the current year at which one of its peaks (not necessarily the first) occurs. You will also be given a date expressed as the number of days from the beginning of the current year. You task is to determine
the number of days from the given date to the next triple peak. The given date is not counted. For example, if the given date is 10 and the next triple peak occurs on day 12, the answer is 2, not 3. If a triple peak occurs on the given date, you should give
the number of days to the next occurrence of a triple peak. 

Input

You will be given a number of cases. The input for each case consists of one line of four integers p, e, i, and d. The values p, e, and i are the number of days from the beginning of the current year at which
the physical, emotional, and intellectual cycles peak, respectively. The value d is the given date and may be smaller than any of p, e, or i. All values are non-negative and at most 365, and you may assume that a triple peak will occur within 21252 days of
the given date. The end of input is indicated by a line in which p = e = i = d = -1.

Output

For each test case, print the case number followed by a message indicating the number of days to the next triple peak, in the form: 

Case 1: the next triple peak occurs in 1234 days. 

Use the plural form ``days'' even if the answer is 1.

Sample Input

0 0 0 0
0 0 0 100
5 20 34 325
4 5 6 7
283 102 23 320
203 301 203 40
-1 -1 -1 -1

Sample Output

Case 1: the next triple peak occurs in 21252 days.
Case 2: the next triple peak occurs in 21152 days.
Case 3: the next triple peak occurs in 19575 days.
Case 4: the next triple peak occurs in 16994 days.
Case 5: the next triple peak occurs in 8910 days.
Case 6: the next triple peak occurs in 10789 days.

/*
题意:人自出生起就有体力,情感和智力三个生理周期,分别为23,28和33天.一个周期内有一天为峰值,
现在给出三个日期,分别对应于体力,情感,智力出现峰值的日期.然后再给出一个起始日期,
要求从这一天开始,算出最少再过多少天后三个峰值同时出现.
类型:中国剩余定理
分析:由 x % 23 = 日期1; x % 28 = 日期2; x % 33 = 日期3.
23,28,33两两互质,很快可以看出,这道题是考中国剩余定理的裸题,直接套上刚学的模版
*/

#include<cstdio>
#include<iostream>
#include<algorithm>
typedef long long LL;
const int maxn = 100005;
void ex_gcd(LL a, LL b, LL &x, LL &y, LL &d){
if (!b) {d = a, x = 1, y = 0;}
else{
ex_gcd(b, a % b, y, x, d);
y -= x * (a / b);
}
}
LL inv(LL t, LL p){//如果不存在，返回-1
LL d, x, y;
ex_gcd(t, p, x, y, d);
return d == 1 ? (x % p + p) % p : -1;
}
LL china(int n, LL *a, LL *m){//中国剩余定理
LL M = 1, ret = 0;
for(int i = 0; i < n; i ++) M *= m[i];
for(int i = 0; i < n; i ++){
LL w = M / m[i];
ret = (ret + w * inv(w, m[i]) * a[i]) % M;
}
return (ret + M) % M;
}
LL p[3]={23,28,33},r[3],d,ans,MOD=21252;//MOD=23*28*33表示三个周期恰好为同一天需要的周期
int main(){
int cas=0;
while(~scanf("%I64d%I64d%I64d%I64d",&r[0],&r[1],&r[2],&d)){
if(r[0]+r[1]+r[2]+d==-4)break;
ans = ((china(3, r, p) - d) % MOD + MOD) % MOD;//获得最小天数
printf("Case %d: the next triple peak occurs in %I64d days.\n", ++cas,ans?ans:MOD);
}
}