ndarray index in numpy
2016-10-15 16:30
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a = np.zeros((10,20,3), np.int) a.shape # (10,20,3) a[0][0].shape a[0, 0].shape # (3,) # (3,) a[0][0:5].shape a[0, 0:5].shape # (5,3) # (5,3) a[0:3][0:5].shape a[0:3, 0:5].shape # (3, 20, 3) # (3, 5, 3) a[0:1, 0:5].shape a[0, 0:5].shape # (1,20,3) # (20,3)
a[0:3][0:5] may get unexpected result. Use a[0:3, 0:5].
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