[HDOJ4788]Hard Disk Drive(水题)
2016-09-21 20:23
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题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4788
题意:1KB有的时候认为是1000B,有的时候是1024B。问两种方法之间的损失。
YY个公式水过。
题意:1KB有的时候认为是1000B,有的时候是1024B。问两种方法之间的损失。
YY个公式水过。
#include <algorithm> #include <iostream> #include <iomanip> #include <cstring> #include <climits> #include <complex> #include <cassert> #include <cstdio> #include <bitset> #include <vector> #include <deque> #include <queue> #include <stack> #include <ctime> #include <set> #include <map> #include <cmath> using namespace std; #define fr first #define sc second #define cl clear #define BUG puts("here!!!") #define W(a) while(a--) #define pb(a) push_back(a) #define Rint(a) scanf("%d", &a) #define Rll(a) scanf("%I64d", &a) #define Rs(a) scanf("%s", a) #define Cin(a) cin >> a #define FRead() freopen("in", "r", stdin) #define FWrite() freopen("out", "w", stdout) #define Rep(i, len) for(int i = 0; i < (len); i++) #define For(i, a, len) for(int i = (a); i < (len); i++) #define Cls(a) memset((a), 0, sizeof(a)) #define Clr(a, x) memset((a), (x), sizeof(a)) #define Full(a) memset((a), 0x7f7f7f, sizeof(a)) #define lrt rt << 1 #define rrt rt << 1 | 1 #define pi 3.14159265359 #define RT return #define lowbit(x) x & (-x) #define onecnt(x) __builtin_popcount(x) typedef long long LL; typedef long double LD; typedef unsigned long long ULL; typedef pair<int, int> pii; typedef pair<string, int> psi; typedef pair<LL, LL> pll; typedef map<string, int> msi; typedef vector<int> vi; typedef vector<LL> vl; typedef vector<vl> vvl; typedef vector<bool> vb; const int maxn = 1010; double tmp; char s[maxn]; map<char, int> q; signed main() { // FRead(); int T, _ = 1; Rint(T); q['B'] = 1;q['K'] = 2;q['M'] = 3;q['G'] = 4; q['T'] = 5;q['P'] = 6;q['E'] = 7;q['Z'] = 8; q['Y'] = 9; W(T) { scanf("%lf[%s", &tmp, s); printf("Case #%d: ", _++); int t = q[s[0]] - 1; double ret = pow(1000.0, t) / pow(1024.0, t); printf("%.2lf%%\n", (double)(1.0 - ret) * 100.0); } RT 0; }
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